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Karolina [17]
3 years ago
8

What is the average atomic mass of titanium on that planet

Chemistry
1 answer:
Licemer1 [7]3 years ago
6 0
Answer:
average atomic mass = 46.8509984 amu

Explanation:
To get the average atomic mass, we will follow these steps:
1- multiply the atomic mass of each isotope by its percentage of abundance
2- add the products

We are given that:
1- The first isotope has an atomic mass of 45.95293 and percentage of abundance equals 72%
2- The second isotope has an atomic mass of 47.94795 and percentage of abundance equals 11%
3- The third isotope has an atomic mass of 49.94479 and percentage of abundance equals 17%

Following the mentioned steps, we can get the average atomic mass as follows:
average atomic mass = (45.95293)(0.72)+(47.94795)(0.11)+(49.94479)(0.17)
                                   = 46.8509984 amu

Hope this helps :)
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Students find the pH of Substance A to be 2.1 and Substance B to be 4.4. They are told Substance C is less acidic than Substance
Slav-nsk [51]

Answer:

the range should be 2.2 to 4.3

Explanation:

I think so because the numbers at the left side of the scale from 1 are more acidic so as it increases it's still acidic but lesser so 1 is more acidic than 2 so I used 2.2 as the beginning of the range because it's less acidic than A even though its a greater number and 4.3 is lesser than 4.4 but its still greater on the scale. frankly speaking I don't feel so correct because it's in decimal so try and compare facts thank you

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Does the temperature of the solvent (water) affect the rate of dissolving?​
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A gas occupies 547 L at 331K. Find its volume at 376K. You must show all of your work to receive credit. Also, name the gas law
zysi [14]

621.4L

Explanation:

Given parameters:

Initial volume = 547L

Initial temperature = 331K

Final temperature = 376K

Unknown:

Final volume = ?

Solution:

The appropriate gas law to use is the Charles's law.

The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.

The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

    \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

 V₁ is the initial volume

 T₁ is the initial temperature

 V₂ is the final volume

 T₂ is the final temperature

Since the unknown is the final volume, we make it the subject of the expression;

   V₂ = \frac{V_{1} }{T_{1} }  x T_{2}  = \frac{547}{331 }  x 376

 V₂ =  621.4L

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

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