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Karolina [17]
3 years ago
8

What is the average atomic mass of titanium on that planet

Chemistry
1 answer:
Licemer1 [7]3 years ago
6 0
Answer:
average atomic mass = 46.8509984 amu

Explanation:
To get the average atomic mass, we will follow these steps:
1- multiply the atomic mass of each isotope by its percentage of abundance
2- add the products

We are given that:
1- The first isotope has an atomic mass of 45.95293 and percentage of abundance equals 72%
2- The second isotope has an atomic mass of 47.94795 and percentage of abundance equals 11%
3- The third isotope has an atomic mass of 49.94479 and percentage of abundance equals 17%

Following the mentioned steps, we can get the average atomic mass as follows:
average atomic mass = (45.95293)(0.72)+(47.94795)(0.11)+(49.94479)(0.17)
                                   = 46.8509984 amu

Hope this helps :)
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Please Help!
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We can use two equations for this problem.<span>

t1/2 = ln 2 / λ = 0.693 / λ
Where t1/2 is the half-life of the element and λ is decay constant.

20 days = 0.693 / λ 
λ   = 0.693 / 20 days        (1) 

Nt = Nο eΛ(-λt)                (2)

Where Nt is atoms at t time, No is the initial amount of substance, λ is decay constant and t is the time taken.
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</span>Hence, 50.01 grams of isotope will remain after 40 days.

<span>
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