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vitfil [10]
3 years ago
12

The air in a living room has a mass of 60 Kg and a specific heat of 1,020 J/kg°C. What is the change in thermal energy of the ai

r when it warms from 20°C to 25°C?
Chemistry
1 answer:
arlik [135]3 years ago
4 0

Answer:

Q = 306 kJ

Explanation:

Given that,

Mass, m = 60 kg

Specific heat, c = 1020 J/kg°C

The temperature changes from 20°C to 25°C.

Let Q be the change in thermal energy. The formula for the heat released is given by :

Q=mc\Delta T

Put all the values,

Q=60\times 1020\times (25-20)\\\\Q=306000\ J\\\\or\\\\Q=306\ kJ

So, 306 kJ is the change in thermal energy.

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An aqueous nacl solution is made using 112 g of nacl diluted to a total solution volume of 1.00 l. calculate the molarity, molal
worty [1.4K]
Q1)
molarity is defined as the number of moles of solute in 1 L of solution.
the NaCl solution volume is 1.00 L
number of moles NaCl  = NaCl mass present / molar mass of NaCl 
NaCl moles = 112 g / 58.5 g/mol = 1.91 mol 
the number of moles of NaCl in 1.00 L of solution is - 1.91 mol 
therefore molarity of NaCl is 1.91 M

Q2) 
molality is defined as the number of moles of solute in 1 kg of solvent.
density is mass per volume. 
density of the solution is 1.08 g/mL. 
therefore mass of the solution is = density x volume 
mass = 1.08 g/mL x 1000 mL = 1080 g
since we have to find the moles in 1 kg of solvent 
mass of solvent = 1080 g - 112 g = 968 g
number of moles of NaCl in 968 g of solvent - 1.91 mol 
therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg
molality of NaCl solution is 1.97 mol/kg


Q3) 
mass percentage is the percentage of mass of solute by total mass of the solution 
mass percentage of solution = mass of solute / total mass of the solution 
mass of solute = 112 g
total mass of solution = 1080 g
mass % of NaCl = 112 g / 1080 g x 100%
therefore mass % of NaCl = 10.4 %
answer is 10.4 %
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