Answer:
See explaination for the prove of the statement.
Step-by-step explanation:
To establish this prove, lets refer back to what we already know.
We know that "If the set of reactions {d1,d2,d3,......dn} in a vector space V over a field f be linearly dependent, then atleast one of the vectors of the set can be expressed as a linear combination of the remaining others.
Please kindly go to attachment for a detailed step by step explaination of the prove.
Answer:
12 CLASSES 10.00=120.00 PLUS 1 MAT FOR 19.95 FOR A TOTAL OF 120.00+19.95=139.95 THUS WE HAVE 12 CLASSES + 1 MAT
Step-by-step explanation:
12 CLASSES 10.00=120.00 PLUS 1 MAT FOR 19.95 FOR A TOTAL OF 120.00+19.95=139.95 THUS WE HAVE 12 CLASSES + 1 MAT
Step-by-step explanation:
Given that,
We have to find the value of m∠E.
Here, two sides are equal, thus it is an isosceles triangle. As the two sides are equal, so their angles must be equal. So, ∠E and ∠D will be equal. Let us assume the measures of both ∠E and ∠D as x.
→ Sum of all the interior angles of ∆ = 180°
→ ∠E + ∠D + ∠F = 180°
→ 116° + x + x = 180°
→ 2x = 180° – 116°
→ 2x = 64°
→ x = 64° ÷ 2
→<u> x = 32°</u>
Henceforth,
→ m∠E = x
→ m∠E = 32°

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