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coldgirl [10]
4 years ago
15

Find the distance, to the nearest tenth, from R(7, –7) to U(–3, 2).

Mathematics
1 answer:
charle [14.2K]4 years ago
4 0

Answer:

<h2>The answer is 13.5 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x_1 - x_2})^{2} +  ({y_1 - y_2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

R(7, –7) to U(–3, 2).

The distance between them is

|RU |  =  \sqrt{ ({7 + 3})^{2}  + ( { - 7 - 2})^{2} }  \\  =  \sqrt{ {10}^{2}  +  ({ - 9})^{2} }  \\  =  \sqrt{100 + 81}  \\  =  \sqrt{181}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  = 13.4536240...

We have the final answer as

<h3>13.5 units to the nearest tenth</h3>

Hope this helps you

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<u>Remove the brackets</u>

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<u>Combine like terms</u>

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Which equation represents the line that passes through points (2, 0) and (6, -8)?
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Answer:

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Step-by-step explanation:

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good luck!

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Write the standard equation of the circle with center (-14, -3) that passes through the point (-5,3),
grin007 [14]

Answer:

(x + 14)^2 + (y + 3)^2 = 117

Step-by-step explanation:

Equation of a circle:

The equation of a circle with center (x_0,y_0) is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In which r is the radius.

Center (-14, -3)

This means that x_0 = -14, y_0 = -3

So

(x - x_0)^2 + (y - y_0)^2 = r^2

(x - (-14))^2 + (y - (-3))^2 = r^2

(x + 14)^2 + (y + 3)^2 = r^2

Passes through the point (-5,3),

This means that when x = -5, y = 3. We use this to find the radius squared. So

(x + 14)^2 + (y + 3)^2 = r^2

(-5 + 14)^2 + (3 + 3)^2 = r^2

r^2 = 117

So, the equation of the circle is:

(x + 14)^2 + (y + 3)^2 = r^2

(x + 14)^2 + (y + 3)^2 = 117

6 0
3 years ago
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