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Arturiano [62]
3 years ago
7

The pendulum with the greatest frequency is one with the

Physics
1 answer:
Jlenok [28]3 years ago
7 0

Answer:

The pendulum with the greatest frequency is one with short length.

Explanation:

A simple pendulum is a device which consists of mass m hanging from the string of length L attached to the some point.When displaced and released its swings back and forth with periodic motion.

The frequency of simple pendulum is given by

    f = \frac{1}{T}

where T is the time period.    

f =1/2π√g/l  

where , l is the length of pendulum

             g is acceleration due to gravity.

The frequency of simple pendulum is defined as how much time or the distance covered by the bob in one second

From the given equation we can find that the frequency of the simple pendulum is<em> inversely proportional</em> to square root of length.Hence the frequency will be maximum if the length of the bob is short.

 

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The spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

<h3>What is double slit experiment?</h3>

The double-slit experiment serves as a proof in current physics that both light and matter may exhibit properties of classically defined waves and particles. It also illustrates the inherently probabilistic nature of quantum mechanical events. Thomas Young carried out the first experiment of this kind employing light in 1802, illustrating how light behaves like a wave. It was formerly believed that light was made up of either waves or particles. About a century later, with the advent of modern physics, it was discovered that light may in fact exhibit behaviour like that of both waves and particles. The identical behaviour of electrons was first shown by Davisson and Germer in 1927, and it was later extended to atoms and molecules.

The separation between the slits, d = 0.05mm = 5×10⁻⁵ m

The distance from the slits to a screen, D = 2.5 m

Let x is the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits,

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We know that the bright fringe is given by :

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So, the spacing between the first-order and second-order bright fringes is :

x = 2λD/d - λD/d

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x = 3 cm

So, the spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

to learn more about double slit experiment go to -

brainly.com/question/28108126

#SPJ4

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