The image distance is 33.3 cm while the image height is 14.2 cm.
<h3>What is a converging lens?</h3>
A converging lens will always have a positive focal length hence, we have to find the object distance as follows;
1/f = 1/v + 1/u
1/12 = 1/v + 1/20
1/v = 1/12 - 1/20
1/v = 0.08 - 0.05
v =33.3 cm
Now;
Magnification = 33.3 cm/20.0 cm =1.67
M = Image height/Object height
1.67 = Image height/8.50 cm
Image height = 1.67 * 8.50 cm
Image height = 14.2 cm
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Answer:
a) W = - 1.752 10⁻¹⁸ J, b) U = + 1.752 10⁻¹⁸ J
Explanation:
a) work is defined by
W = F . x
the bold letters indicate vectors, in this case the force is electric
F = q E
we substitute
F = q E x
the charge of the electron is
q = - e
F = - e E x
let's calculate
W = - 1.6 10⁻¹⁹ 365 3 10⁻²
W = - 1.752 10⁻¹⁸ J
b) the change in potential energy is
U = q ΔV
the potential difference is
ΔV = - E. Δs
we substitute
U = - q E Δs
the charge of the electron is
q = - e
U = e E Δs
we calculate
U = 1.6 10⁻¹⁹ 365 3 10⁻²
U = + 1.752 10⁻¹⁸ J
Answer:
The water releases energy which causes the water molecules to have less kinetic and potential energy, changing their configuration from liquid to solid.
Explanation:
Confirmed through test.
Answer:
θ = 56.09°
Explanation:
Given that
h = 8.5 ft
speed ,u= 28 ft/s
We know that acceleration due to gravity g
g= 32.2 ft/s²
The maximum height h is given as
Now by putting the values
θ = 56.09°
Therefore the angle will be θ = 56.09°