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Artemon [7]
3 years ago
14

The expression 35 exponet 2 is equivalent to the product of two perfect squares (each greater than 1). You can find the two

Mathematics
1 answer:
raketka [301]3 years ago
7 0

Answer:

tb

Step-by-step explanation:

You might be interested in
Which geometric object is defined as the set of all points in a plane at a given distance from a given point
hodyreva [135]

Answer:

Circle

Step-by-step explanation:

This object is what we call "circle". All the points in the circle are at the same distance from a given point which is the center of the circle. Moreover, the distance between the center and every point on the circle is called "radius". Higher values for the radius imply points at a higher distance from the center.

Additionally, we can calculate the perimeter of the circle, or the circumference, with the following formula:

circumference = 2*(radius) pi

Where pi is an irrational number usually used as 3.14.

If you have doubts, try to draw a circle and measure the distance between the center and any point on the circle.

8 0
3 years ago
How many solutions does the system have?<br> 8x + 2y = 14<br> (8x + 2y = 4
e-lub [12.9K]

Answer:

zero

Step-by-step explanation:

they are parallel once graphed

3 0
3 years ago
The White Russian cocktail contains vodka, Tia Maria and milk in the ratio of 5:2:3. To make the cocktail for a party the barman
stellarik [79]

Answer:

1) 600cm^3            2) 10 glasses

Step-by-step explanation:

x = total amount in ml

(3/10)x = 180ml (MILK)

x = 600ml

(2/10)600 = 120ml (TIA MARIA)

(1/2)600 = 300ml (VODKA)

<em>1) 600cm^3</em>

<em>2) 600ml : 60ml = 10 (GLASSES)</em>

6 0
1 year ago
Determine which of the indicated column vectors are eigenvectors of the given matrix
gladu [14]
]Eigenvectors are found by the equation (A-\lambda I) \vec{v} = 0$ implying that \det(A-\lambda I) = 0. We then can write:

A-\lambda I = \left [ \begin{array}{cc} 4-\lambda & 2 \\ 5 & 1-\lambda \end{array}\right ] 

And:

\det(A-\lambda I) = (4-\lambda)(1-\lambda) - 10 = 0 

Gives us the characteristic polynomial:

\lambda^2 - 5 \lambda -6 = 0 \implies \lambda_1 = -1, \lambda_2 = 6

So, solving for each eigenvector subspace:

\left [ \begin{array}{cc} 4 & 2 \\ 5 & 1 \end{array} \right ] \left [ \begin{array}{c} x \\ y \end{array} \right ] = \left [ \begin{array}{c} -x \\ -y \end{array} \right ]

Gives us the system of equations:

4x + 2y = -x \newline 5x + y = - y 

Producing the subspace along the line y = -\frac{5}{2} x

We can see then that 3 is the answer. 



7 0
3 years ago
PLEASE HELP!!! WILL GIVE BRAIN!!!What has to be true if you want to solve a quadratic?
asambeis [7]

Answer:

Step-by-step explanation:

you have to have a quadratic equation, not sure what your question is,

6 0
2 years ago
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