Answer:
The answer is no though, the point (1,-1) is below both.
Step-by-step explanation:
So the two inequalities are y≤-3x+3 and 3x+8y≥3
With inequalities you have to know a few things. First, when you graph you may have to use non solid lines. for instance, if you had x<5, 5 would not be part of the answer because it is only answers less than 5. so you represent this by making a dashed line that says "you cannot include values on this line". Second, with algebra, if you multiply both sides by a negative it flips the inequality. for instance -y > 54 you would multiply (or divide) by -1 and it would change to y < -54. Third, when graphing an inequality, treat it like an equation and graph the line as if it were said equation(with solid or dashed lines as needed) then, if it is y > f(x) you shade in the section above the line and y < f(x) shades in below. The shaded part is your answer basically. Now lets get into yours.
y≤-3x+3
It is already in the form y = f(x) so grapht he line 3x + 3 with a solid line since it is y is less than or equal to, then shade below that line.
3x+8y≥3
First get it so y is by itself
3x+8y≥3
8y≥3 - 3x
y ≥ 3/8 - 3/8 x
Now grapht his line with a solid line and shade the area above it.
Now, the shaded area below between y ≥ 3/8 - 3/8 x and y≤-3x+3 and the lines are your answer, so you need to check if the point (1, -1) is in this shared shaded area or on one of the lines.
The answer is no though, the point (1,-1) is below both.
=L