Answer:
HL
Step-by-step explanation:
The things that are congruent between the 2 triangles are the 90° angles and the hypotenuses and legs. HA and LA only work with the acute angles, not right angles, and AA isn't a way of proving things to be congruent, meaning that HL is the answer
Answer:
a) 3rd degree
b) negative
c) 2
d) zero
e) the graph approaches +∞, -∞
Step-by-step explanation:
a) because two turns
b) because the function does not approach y=+∞ as x approaches x=+∞
c) the graph switches direction twice
d) from observation
e) it appears so, and is the nature of polynomials
Answer:
OG = 8.7
Step-by-step explanation:
The angle a tangent makes with a radius at the point of tangency is a right angle. That means ΔOGH is a right triangle.
The tangents to a circle from an external point are congruent, so GH = GI = 6.3. Now we know the sides of the right triangle are of lengths 6 and 6.3. The hypotenuse, OG is found using the Pythagorean theorem.
OG² = OH² +GH²
OG² = 6² +6.3² = 75.69
OG = √75.69 = 8.7
The length of OG is 8.7 units.
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<em>Additional comment</em>
You might recognize this triangle as a 0.3 multiple of the Pythagorean triple (20, 21, 29).
$200.78 multiplied by 15 equals <span>$3,011.70. So your answer is D)</span>
The thief originally stole 64 plants.
<h3>What is arithmetic?</h3>
In mathematics, it deals with numbers of operations according to the statements.
Here,
Let the number of plants originally stolen by the thief be x.
On the way out, the thief meets three security guards, one after another. To each security guard, the thief is forced to give one-half of the plants that he still had, plus 2 more.
Here,
For gourd 1 the planet is given = 1/2 x
For gourd 2 the planet is given = 1/2 * 1/2 x = 1/4 x
For gourd 3 the planet is given = 1/2*1/4 x = 1/8 x
Total plant given to the gourds = 1/2x +1/4x +1/8x + 2 = 7/x/8x +2
Finally, the thief leaves the nursery with 10 plants
x - 7x/8 + 2 = 10
x/8 = 8
x = 64
Thus, the thief stole 64 plants.
Learn more about arithmetic here:
brainly.com/question/14753192
<h3>
#SPJ1</h3>
