What is -18+11= a. postive b. negative c. zero
2 answers:
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Cos(x) = sin(x + 20o) Use the double cos angle formula
Cos(x) = sin(x)*cos(20) + cos(x)*sin(20) Divide through by cos(x). Tanx = sin(x)/cos(x)
1 = tan(x)*cos(20) + sin(20) Subtract sin(20) from both sides.
1 - sin(20) = tan(x)*cos(20) Calculate the value of 1 - sin(20)
0.65798 = tan(x) * 0.939692 Divide by cos(20)
tan(x) = 0.65795/0.939692
tan(x) = 0.70021 Take the inverse of 0.7) = tan(x)
x = tan-1(0.70021)
x = 35 degrees as expected.
Problem Two
The easiest way to do this is to pick random values and try it. The two acute angles are complementary. So 25 and 65 are random enough.
Let A = 25
Let C = 65
A
Tan(25) = sin(25)/sin(65) ; tan(25) = 0.4663.
sin(25)/sin(65) = 0.4663 Answer
B
Sin(90 - C) = Sin(A)
Tan(90 - A) = Tan(C)
So the question becomes Cos(A) = Tan(C) / sin(A)
Cos(25) = Tan(65)/Sin(25)
0.906 = ? 5.07 This statement isn't true.
C
Sin(65) = Cos(25)/Tan(65)
.906 = 0.4226 C is not the correct answer.
D
D isn't true. The tan does not relate that away. You can find it for yourself.
Cos(A) = Tan(C) You should get 0.906 = 2.14
E
Sin(C) = Cos(A) / Tan(A) I'll leave you to show this is wrong.
Problem 3
The diagram below is for this problem. Cos(x) = 50/100 = 0.5
x = cos-1(0.5)
x = 60 degrees.
Part 2
Sin(60) = opposite / hypotenuse
opposite = sin(60) * hypotenuse
opposite = 86.61 Be sure and round this to whatever the question says to round it to.
This question is incomplete because it lacks the appropriate attachment containing the argument of Paul and Manuel
Kindly find attached the appropriate attachment necessary to solve this question.
The attachment was sourced online
Answer:
a) Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X
Step-by-step explanation:
From the above question, we are given two shapes: Cone W and Square Pyramid
Cone W: Radius = 8cm, Height = 5cm
Volume of a Cone = 1/3 πr²h
Where π = 3.14
Volume of Cone X = 1/3 × 3.14 × 8² × 5
= 334.93cm³
For Square pyramid X
Volume = 1/3 × Base Area × Height
Base Area of Cone W = Base Area of square pyramid X = πr²
Where π = 3.14
Base area = 3.14 × 8² = 200.96cm²
Height of Square pyramid X = Height of Cone W = 5cm
Volume of Square pyramid = 1/3 ×200.96cm² × 5cm
= 334.93cm³
Therefore, from my above calculation and compared with the arguments of Paul and Manuel, Option a) "Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X" is the correct option.
The reason why is because the correct formula for the volume of a square pyramid = 1/3 × Base area × Height
This was the formula Paul used.
Manuel on the other hand used the formula: Base Area × Height to find the volume of cone W. This formula is wrong.
Option a, is the correct answer.
