Let x be the number of defective cell phones. It is given that in batch of 100, on average 5 are defective.
let p be the probability of defective cell phone.
p = 5/100 = 0.05
Let n be size of random sample, n=30
Here out of 30 we want to find probability that 2 will be defective. It means 30-2 =28 cell phones will be non defective.
The probability of getting non defective cell phone is 1- p=1-0.05 =0.95
The probabability of getting 2 defective is
P(X=2) = number of ways selecting 2 from 30 * probability 2 defective * probability of 28 non defective
Now number of ways of selecting 2 cell phone from 30 is
30C2 = 
= 
= 
= (30*29) /2
30C2 = 435
P(X=2) = 30C2 * (0.05)^2 * (0.95)^28
= 435 * 0.0025 * 0.2378
P(X=2) = 0.2586
Probability of getting 2 defective out of 30 is 0.2586
Answer: 15 boxes
Step-by-step explanation:
From the question, we are informed that Denise wants to cover a 21.75 square foot wall with weathered wood and that each box of weathered wood contains 1.5 square feet of wood.
The number of boxes of weathered wood that she need will be calculated by dividing 21.75 square feet by 1.5 square feet. This will be:
= 21.75/1.5
= 14.5
= 15 boxes approximately
Total Cost = 55+0.35x
X represents the amount of minutes you spend talking on the phone.
C = total number of candy
.4(c) = 8 pieces of candy
Divide c by .4: c= 20
20-8=12
Ed has 12 pieces of candy at home
Radii and chord form an equilateral triangle. The angle of the larger segment is

.
The length of the larger segment is