Answer: i don't see the problem
Step-by-step explanation:
Answer:
5^3 y^5
125 y^5
Step-by-step explanation:
5y^3/(5y)^-2
Distribute the exponent in the denominator
5y^3/(5 ^-2 y^-2)
A negative exponent in the denominator brings it to the numerator
5y^3 5 ^2 y^2
Combine like terms
5 * 5^2 * y^3 5^2
We know that a^b * a^c = a^(b+c)
5^(1+2) * y^( 3+2)
5^3 y^5
125 y^5
Answer:
The 95% confidence interval for the mean change in blood pressure,
, is 1.744 <
< 2.816
Step-by-step explanation:
The parameters given are;
The number of people in the sample, n = 9
The average drop in blood pressure,
= 2.28 points
The standard deviation, σ = 0.82
The confidence level = 95%
The formula for confidence interval with a known mean is given as follows;
![CI=\bar{x}\pm z_{\alpha/2} \dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=CI%3D%5Cbar%7Bx%7D%5Cpm%20z_%7B%5Calpha%2F2%7D%20%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
Where:
= z - score at 95% confidence level = 1.96
We therefore have;
![CI=2.28 \pm 1.96 \times \dfrac{0.82}{\sqrt{9}}](https://tex.z-dn.net/?f=CI%3D2.28%20%5Cpm%201.96%20%5Ctimes%20%5Cdfrac%7B0.82%7D%7B%5Csqrt%7B9%7D%7D)
Which gives the 95% confidence interval for the mean change in pressure,
, is given as follows;
1.744 <
< 2.816
Answer:
At the end of two years Mrs.Scott earned $1929.36 (i rounded the dec.)
Step-by-step explanation:
A= p(1+r)^t
P= 1750
r= .05
t= 2
A= 1750(1+.05)^2
A= 1929.375
Answer:
-27.6
Step-by-step explanation:
I'm smart but probably shouldn't use my answer