Answer:
the frequency of allele B is 0.7 and allele b is 0.3 in population’s gene pool.
Step-by-step explanation:
Allele frequency is how often an allele occurs in a gene pool relative to the other alleles for that gene
<u>Genotype</u> <u> No. of Individuals</u><u> </u> <u>No. of Allele </u><u>B</u> <u>No. of Allele</u><u> b </u>
BB 30 30*2 =60 30*0 =0
Bb 10 10*1 =10 10*1=10
bb 10 10 *0 =0 10*2=20
Total 50 70 30
Total no. of alleles = 70+30 =100
The frequency of allele B :
:
:
The frequency of allele b :
:
:
Hence the frequency of allele B is 0.7 and allele b is 0.3 in population’s gene pool.
Answer:
True
Step-by-step explanation:
Descriptive statistics gives certain information about the data that helps us understand it better. For example, If you have a data set containing the number of customers that visit a shopping mall per day, the proportion of male customers or the average number of customers over period of time are some examples of descriptive statistics.
Inferential statistics uses sample data from a larger population to make certain inferences and draw conclusions about that population based on some standard procedures. Some examples of methods in inferential statistics are, Confidence intervals, Hypothesis Testing and Regression analysis
The minimum electric rate in cents per kwh for which the 12-year total cost will be less for the first freezer is 8.61 cents
<h3>How to calculate the rate?</h3>
Let x = minimum electric rate (Cents/kWh)
Total months in 12 years is 12*12 = 144 m
1st freezer
Total cost over 12 years is
623.95 (cost) + (90 kWh/m)*(144 m)(x/100 $/kWh)
= 623.95 + 129.6x
2nd freezer
Total cost over 12 years is
500 + 100*144*(x/100)
= 500 + 144x
For the 1st freezer to cost less over 12 years,
623.95 + 129.6x < 500 + 144x
123.95 < 14.4x
8.61 < x
The minimum rate is 8.61 cents per kWh
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