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tankabanditka [31]
3 years ago
11

A 60-meter-long wire is divided into two parts such that the length of one part is 3/5 parts the length of the other. Determine

the length of each part
Mathematics
2 answers:
NISA [10]3 years ago
8 0

Answer:

37.5 m, 22.5 m

Step-by-step explanation:

Let length of first part be x

Length of second part be 3/5x

x + 3/5x = 60

5x + 3x = 60

8x = 300

x = 300/8 = 37.50 m

Second part is 3/5x

3/5 x 37.50 = 22.50 m

Sidana [21]3 years ago
7 0

Answer:

36 meters and 24 meters.

Step-by-step explanation:

60 \times 3/5\\180/5=36

60 \times (1-3/5)\\60 \times 2/5\\120/5=24

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The answer is -8b - 32

to get the answer you distribute the 8 to -b and -4

8 • -b = -8b and 8 • -4 = -32
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4 years ago
Every spring the grade four students play the grade five students in softball. The graph shows their scores.
bezimeni [28]

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B

Step-by-step explanation:

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3 years ago
If an outfit consist of jeans, shirt, a sweater and a scarf, how many different outfits can a person make from one pair of jeans
Natalija [7]

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24

Step-by-step explanation:

Just multiply the choices together.

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4 0
4 years ago
Simplify 4+3(7+4*2) - 100​
bazaltina [42]

Answer:

4+3(7+4*2) - 100​ = -51

Step-by-step explanation:

4+3(7+4*2) - 100​

= 4 + 3 (15) - 100

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6 0
4 years ago
Paul has 2/3 as many postcards as Shawn. The number of postcards Shawn has is 4/5 of the number of postcards Tim has. If the thr
ahrayia [7]

Tim has 56 more postcards than Paul.

Step-by-step explanation:

Total postcards boys have = 280

Let,

x = Paul's postcards

y = Shawn's postcards

z = Tim's postcards

According to given statement;

x + y + z = 280      Eqn 1

x=\frac{2}{3}y                   Eqn 2

y = \frac{4}{5}z                   Eqn 3

Putting value of y from Eqn 3 in Eqn 2

x=\frac{2}{3}*\frac{4}{5}z\\\\x=\frac{8}{15}z            Eqn 4

Putting value of x and y from Eqn 4 and Eqn 3 in Eqn 1

\frac{8}{15}z+\frac{4}{5}z+z=280\\\\\frac{8z+12z+15z}{15}=280\\\\\frac{35z}{15}=280\\\\

Multiplying both sides by \frac{15}{35}

\frac{15}{35}*\frac{35}{15}z=280*\frac{15}{35}\\z=120

Putting z=120 in Eqn 3

y=\frac{4}{5}*120\\y=96

Putting y=96 in Eqn 2

x=\frac{2}{3}*96\\x=64

Difference of Tim and Paul = 120-64 = 56

Tim has 56 more postcards than Paul.

Keywords: linear equation, substitution method

Learn more about substitution method at:

  • brainly.com/question/10557938
  • brainly.com/question/10600222

#LearnwithBrainly

7 0
3 years ago
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