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3 years ago

If a dozen donuts cost twelve cents, how much does a hundred donuts cost?

Mathematics

1 answer:

Rudiy273 years ago

5 0

A hundred donuts cost 1 dollar

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Write the relation as a set of ordered pairs.

ankoles [38]

Answer:

option B is the answer.

7 0

3 years ago

Steven is taking out a loan in the amount of $5,000. His choices are a 3-year loan at 5% simple interest and a 5 -year loan at 4

Andre45 [30]

I do believe it’s 250$

**The first choice:**
Principal: 5,000$
Rate(%): 5
Time(year): 3 years
A: 5,750$

**Second choice**
Principal: 5,000$
Rate(%): 4%
Time(year): 5 years
A: 6,000$

6,000-5,750=250$

Hope this helps!

8 0

3 years ago

Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

7 0

3 years ago

Simple 9th grade math

Liono4ka [1.6K]

Answer:

-1078

Step-by-step explanation:

To find the nth term in an arithmetic sequence we use the following formula

aₙ=a₁+(n-1)*d

Where a₁ is the first time, and d is the common difference (in this case -20)

So we have

2+(55-1)*-20

2+(54)*-20

2-1080

-1078

5 0

3 years ago

What is The cube of the product of 3 and x

Anni [7]

Answer: 9

Step-by-step explanation:

5 0

3 years ago