Answer:
An acid is a substance that releases H⁺ in aqueous solution.
Explanation:
There are different acid-base theories, such as Arrhenius, Bronsted-Lowry, Lewis, etc.
According to the Arrhenius theory, an acid is a substance that releases H⁺ in aqueous solution.
HCl(aq) → H⁺(aq) + Cl⁻(aq)
On the other hand, according to the Arrhenius theory, a base is a substance that releases OH⁻ in aqueous solution.
NaOH(aq) → Na⁺(aq) + OH⁻(aq)
The energy of the carbide released is 7262.5MJ.
<h3>What is the energy?</h3>
We know that the reaction between calcium oxide and carbon occurs in accordance with the reaction; . The reaction is seen to produce 464.8kJ of energy per mole of carbide produced.
Number of moles of produced = 1000 * 10^3 g/64 g/mol
= 15625 moles of calcium carbide
If 1 mole of transfers 464.8 * 10^3 J
15625 moles of calcium carbide transfers 15625 moles * 464.8 * 10^3 J/ 1 mol
= 7262.5MJ
Learn more about reaction enthalpy:brainly.com/question/1657608
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Answer:
d. Bar graph
Explanation:
a. Line graph - this type of graph is best for continuous data, such as how a the sales of a particular cereal drop over time
b. Pie chart - this is best for % data, such as looking at the % of different nutrients (carbohydrates, fats, proteins) in a cereal
C. Stem-and-leaf plot - presents quantitative data such as the ages of people who buy a brand of cereal
d. Bar graph - this is best for plotting different numbers in distinct categories to compare them to one another
The molar mass of the Carbon-12 from the periodic table is given to be 12.011 g. Multiply this mass with the number of moles given.
(0.25 moles) x (12.011 g / mole) = 3 g
Thus, the mass of 0.25 moles of carbon-12 is 3 g.
Answer:
28.28 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have two different values of V and P:
<em>P₁V₁ = P₂V₂</em>
<em></em>
P₁ = 700.0 mm Hg, V₁ = 4.0 L.
at burst: P₂ = 99.0 mm Hg, V₂ = ??? L.
<em>∴ V₂ = P₁V₁/P₂</em> = (700.0 mm Hg)(4.0 L)/(99.0 mm Hg) = <em>28.28 L.</em>