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Shtirlitz [24]
2 years ago
7

What does chlorine (Cl-) do for sodium (Na+)? What tasty substance is produced when this

Chemistry
1 answer:
solong [7]2 years ago
7 0
Pretty sure it’s salt
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What does electric current measure?
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Explanation:

Electric current in a wire, where the charge carriers are electrons, is a measure of the quantity of charge passing any point of the wire per unit of time. ... Current is usually denoted by the symbol I. Ohm's law relates the current flowing through a conductor to the voltage V and resistance R; that is, V = IR.

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Atomic Radius________across (left to right) a period and______down a group.
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3 years ago
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What is the speed of a car that covers 250 miles in 5 hours?
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5 0
2 years ago
A worker is told her chances of being killed by a particular process are 1 in every 300 years. Should the worker be satisfied or
Pavlova-9 [17]

Answer:

(a) Yes, he should be worried. The Fatal accident rate (FAR) is too high according to standars of the industry. This chemical plant has a FAR of 167, where in average chemical plants the FAR is about 4.

(b) FAR=167 and Death poer person per year = 0.0033 deaths/year.

(c) The expected number of fatalities on a average chemical plant are one in 12500 years.

Explanation:

Asumming 50 weeks of work, with 40 hours/week, we have 2000 work hours a year.

In 300 years we have 600,000 hours.

With these estimations, we have (1/600,000)=1.67*10^(-6) deaths/hour.

If we have 2000 work hours a year, it is expected 0.0033 deaths/year.

1.67*10^{-6} \frac{deaths}{hour}*2000 \frac{hours}{year}=0.0033 deaths/year

The Fatal accident rate (FAR) can be expressed as the expected number of fatalities in 100 millions hours (10^(8) hours).

In these case we have calculated 1.67*10^(-6) deaths/hour, so we can estimate FAR as:

FAR=1.67*10^{-6} \frac{deaths}{hour}*10^{8}  hours=1.67*10^{2} =167

A FAR of 167 is very high compared to the typical chemical plants (FAR=4), so the worker has reasons to be worried.

If we assume FAR=4, as in an average chemical plant, we expect

4\frac{deaths}{10^{8} hour} *2000\frac{hours}{year}=8*10^{-5} \frac{deaths}{year}

This is equivalent to say

\frac{1}{8*10^{-5} } \frac{years}{death}=1.25*10^{4} \frac{years}{death} =12500 \, \frac{years}{death}

The expected number of fatalities on a average chemical plant are one in 12500 years.

4 0
3 years ago
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