What does chlorine (Cl-) do for sodium (Na+)? What tasty substance is produced when this

At 298 K, what is the Gibbs free energy change (ΔG) for the following reaction?

9966 [12]

Answer:

(a). The Gibbs free energy change is 2.895 kJ and its positive.

(b). The Gibbs free energy change is 34.59 J/mole

(c). The pressure is 14924 atm.

(d). The Gibbs free energy of diamond relative to graphite is 4912 J.

Explanation:

Given that,

Temperature = 298 K

Suppose, density of graphite is 2.25 g/cm³ and density of diamond is 3.51 g/cm³.

$\Delta H\ for\ diamond = 1.897 kJ/mol$

$\Delta H\ for\ graphite = 0 kJ/mol$

$\Delta S\ for\ diamond = 2.38 J/(K mol)$

$\Delta S\ for\ graphite = 5.73 J/(K mol)$

(a) We need to calculate the value of $\Delta G$ for diamond

Using formula of Gibbs free energy change

$\Delta G=\Delta H-T\Delta S$

Put the value into the formula

$\Delta G= (1897-0)-298\times(2.38-5.73)$

$\Delta G=2895.3$

$\Delta G=2.895\ kJ$

The Gibbs free energy change is positive.

(b). When it is compressed isothermally from 1 atm to 1000 atm

We need to calculate the change of Gibbs free energy of diamond

Using formula of gibbs free energy

$\Delta S=V\times\Delta P$

$\Delta S=\dfrac{m}{\rho}\times\Delta P$

Put the value into the formula

$\Delta S=\dfrac{12\times10^{-6}}{3.51}\times999\times10130$

$\Delta S=34.59\ J/mole$

(c). Assuming that graphite and diamond are incompressible

We need to calculate the pressure

Using formula of Gibbs free energy

$\beta= \Delta G_{g}+\Delta G+\Delta G_{d}$

$\beta=V(-\Delta P_{g})+\Delta G+V\Delta P_{d}$

$\beta=\Delta P(V_{d}-V_{g})+\Delta G$

Put the value into the formula

$0=\Delta P(\dfrac{12\times10^{-6}}{3.51}-\dfrac{12\times10^{-6}}{2.25})\times10130+2895.3$

$0=-0.0194\Delta P+2895.3$

$\Delta P=\dfrac{2895.3}{0.0194}$

$\Delta P=14924\ atm$

(d). Here, $C_{p}=0$

So, The value of $\Delta H$ and $\Delta S$ at 900 k will be equal at 298 K

We need to calculate the Gibbs free energy of diamond relative to graphite

Using formula of Gibbs free energy

$\Delta G=\Delta H-T\Delta S$

Put the value into the formula

$\Delta G=(1897-0)-900\times(2.38-5.73)$

$\Delta G=4912\ J$

Hence, (a). The Gibbs free energy change is 2.895 kJ and its positive.

(b). The Gibbs free energy change is 34.59 J/mole

(c). The pressure is 14924 atm.

(d). The Gibbs free energy of diamond relative to graphite is 4912 J.

7 0

2 years ago

All elements in the same group (Column) on a periodic table have what in common?

vesna_86 [32]

They have the same number of valence electrons.

5 0

3 years ago

Please help i got no clue how to do dis

mamaluj [8]

Answer:

Sulfur's Atomic #: 16

Fluorine's Atomic #: 9

Antimony's Atomic #: 51

Silver's Atomic #: 47

Rubidium's Atomic #: 37

Copper's Atomic #: 29

Tin's Atomic #: 50

Mercury's Atomic #: 80

Promethium's Atomic #: 61

3 0

2 years ago

In a _____ molecules move just enough to stay close together but not to stick

aliina [53]

Answer:

I think it might be liquid

4 0

2 years ago

Read 2 more answers

Name the compound and Determine the number of atoms.<br><br> 22g NH3

Bezzdna [24]

Answer:

Compound is: Ammonia

Number of NH3 Molecules: 7.7905x10^23

Number of N atoms: 7.7905x10^23

Number of H atoms: 2.337x10^24

Explanation:

In order to obtain number of particles: We first need to calculate number of moles which is equal Mass/Molar mass (N=14 H=1)

Thus Number of moles equal 22/14+3 = 1.294117647 Moles

Number of particles equal Number of moles multiply Avogadro's number = 1.294117647 x 6.02x10^23 = 7.7905x10^23 Molecules of NH3

Since that each molecule contains one Nitrogen atom therefore, Number of molecules = number of atoms while each molecule contains 3 Hydrogen atoms therefore, Number of hydrogen atoms = 3x Number of Molecules = 2.337x10^24

4 0

2 years ago