Answer:
percent yield = 56.6 %
Explanation:
Data given:
mass of Ethylene gas (C₂H₄) = 140 g
actual yield of 1,2-Dichloro Ethane (C₂H₄Cl₂)= 280 g
percent yield of 1,2-Dichloro Ethane (C₂H₄Cl₂) = ?
Reaction Given:
C₂H₄ + Cl₂ -------> C₂H₄Cl₂
Solution:
First we have to find theoretical yield.
So,
Look at the reaction
C₂H₄ + Cl₂ -----—> C₂H₄Cl₂
1 mol 1 mol
As 1 mole of C give 1 mole of CH₄
Convert moles to mass
molar mass of C₂H₄ = 2(12) + 4(1)
molar mass of C₂H₄ = 24 + 4
- molar mass of C₂H₄ = 28 g/mol
molar mass of C₂H₄Cl₂ = 2(12) + 4(1) + 2(35.5)
molar mass of C₂H₄Cl₂ = 24 + 4 + 71
- molar mass of C₂H₄Cl₂ = 99 g/mol
Now
C₂H₄ + Cl₂ -----—> C₂H₄Cl₂
1 mol (28 g/mol) 1 mol (99 g/mol)
28 g 99 g
28 grams of Ethylene gas (C₂H₄) produce 99 grams of C₂H₄Cl₂
So
if 28 g of C₂H₄ produce 99 g of C₂H₄Cl₂ so how many grams of C₂H₄Cl₂ will be produced by 140 g of C₂H₄.
Apply Unity Formula
28 g of C₂H₄ ≅ 99 g of C₂H₄Cl₂
140 g of C₂H₄≅ X of C₂H₄Cl₂
Do cross multiply
mass of C₂H₄Cl₂ = 99 g x 140 g / 28 g
mass of C₂H₄Cl₂ = 495 g
So the Theoretical yield of 1,2-Dichloro Ethane (C₂H₄Cl₂)= 495 g
Now Find the percent yield of 1,2-Dichloro Ethane (C₂H₄Cl₂)
Formula Used
percent yield = actual yield /theoretical yield x 100 %
Put value in the above formula
percent yield = 280g / 495 g x 100 %
percent yield = 56.6 %
percent yield of 1,2-Dichloro Ethane (C₂H₄Cl₂) = 56.6 %
