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3 years ago

What is 2.1 with 1 repeating as a mixed fraction

Mathematics

1 answer:

zubka84 [21]3 years ago

5 0

Answer:

the answer is B

Step-by-step explanation:

1. convert the mixed number choices to improper fractions

2. type each improper fraction into a calculator

3. see which one comes out as 2.111111111

4. find out that it's B and you'll B happy (see what I did there, it's a pun)

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Please answer this correctly

liraira [26]

Answer:
2156/9

Explanation:
The question states all the necessary values that we need for the ratio. The company created 2156 board games and 9 card games.

However, what we need to pay attention to here is the order of the ratio.

Because the question is “What is the ratio of the number of board games to the number of card games”, we know that we need to write the ratio so the number of board games is first.

Additionally, ratios can also be written like fractions. The first number of the ratio would be the top number/numerator in fraction form.

Therefore, the ratio of the number of board games to the number of card games is 2156:9

I hope this helps!

6 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Zolol [24]

Answer:

Step-by-step explanation:

Triangle DEF is a right angle triangle.

From the given right angle triangle,

DE represents the hypotenuse of the right angle triangle.

With ∠E as the reference angle,

EF represents the adjacent side of the right angle triangle.

DF represents the opposite side of the right angle triangle.

To determine EF, we would apply

trigonometric ratio

Cos θ = opposite side/hypotenuse. Therefore,

Cos 49 = EF/8

EF = 8Cos49 = 8 × 0.6561

EF = 5.2488

Rounding to the nearest tenth, it becomes 5.2

3 0

3 years ago

(brainliest) please help me out with this graph! :)

Elenna [48]

Answer:

like write an equation? If so it's a 0 slope

Step-by-step explanation:

6 0

3 years ago

Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true

IgorLugansk [536]

Answer:

(a) 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

Step-by-step explanation:

We are given that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.75.

(a) Also, the average porosity for 20 specimens from the seam was 4.85.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average porosity = 4.85

$\sigma$ = population standard deviation = 0.75

n = sample of specimens = 20

$\mu$ = true average porosity

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $4.85-1.96 \times {\frac{0.75}{\sqrt{20} } }$ , $4.85+1.96 \times {\frac{0.75}{\sqrt{20} } }$ ]

= [4.52 , 5.18]

Therefore, 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) Now, there is another seam based on 16 specimens with a sample average porosity of 4.56.

The pivotal quantity for 98% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average porosity = 4.56

$\sigma$ = population standard deviation = 0.75

n = sample of specimens = 16

$\mu$ = true average porosity

Here for constructing 98% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 98% confidence interval for the true mean, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98 {As the critical value of z at 1% level

of significance are -2.3263 & 2.3263}

P(-2.3263 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.3263$ ) = 0.98

P( $\bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $4.56-2.3263 \times {\frac{0.75}{\sqrt{16} } }$ , $4.56+2.3263 \times {\frac{0.75}{\sqrt{16} } }$ ]

= [4.12 , 4.99]

Therefore, 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

7 0

4 years ago

Brian measures his height at 160cm to the nearest 10cm.

Elan Coil [88]

Answer:

170 cm is the tallest

3 0

3 years ago