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Gelneren [198K]
3 years ago
15

Thomas buys 6 souvenirs for his friends and family. Each gift takes up 1/15 of his suitcase. If he has two suitcases, how much r

oom is left for his own belongings in his suitcases?
Mathematics
1 answer:
Gala2k [10]3 years ago
6 0

Answer:

<u>Thomas still has 1 3/5 suitcases available for his own belongings.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Number of souvenirs bought by Thomas = 6

Space that each souvenir takes of Thomas suitcase = 1/15

Number of Thomas suitcases = 2

2.  How much room is left for his own belongings in his suitcases?

Let's find out how much space the souvenirs take:

Number of souvenirs * Space that each souvenir takes

6 * 1/15 = 6/15 = 2/5 (Dividing by 3 the numerator and the denominator)

The souvenirs take 2/5 of one suitcase.

Now, we can calculate the room that is left for Thomas' belongings.

2 Suitcases - 2/5 for the souvenirs

2 - 2/5 = 10/5 - 2/5 = 8/5 = 1 3/5

<u>Thomas still has 1 3/5 suitcases available for his own belongings.</u>

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2 years ago
The perimeter of a rectangular garden is 374.
marusya05 [52]

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3 years ago
How do i solve using the substitution method?<br> x+y=-1 <br> y=-2x
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Answer:

10 minutes

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Since you can do 6 flyers each minute, the rate would go at 6x, with x being minutes. You initially did 80, so the equation for you would be y=6x+80.

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