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3 years ago

What describes how fast an object is moving and in what direction

2 answers:

6 0

Speed is a description of how fast an object moves; velocity is how fast and in what direction it moves. In physics, velocity is speed in a given direction. When we say a car travels at 60 km/h, we are specifying its speed.

Reptile [31]3 years ago

4 0

Answer

velocity is how fast and in what direction it moves.

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A 64 kg cross-country skier glides over snow. Thecoefficient

BaLLatris [955]

Answer:

The distance traveled by the skier is 5.309 km

Solution:

As per the question:

Mass of the skier, m = 64 kg

Coefficient of friction between the ski and the snow, $\mu_{k} = 0.50$

Mass of snow, M = 5.0 kg

Now,

To calculate the distance, 's' traveled by the skier, in order to melt 5.0 kg of snow:

We know that:

$f = \mu_{k}N$

where

$\mu_{k}$ = coefficient of friction

N = Normal Reaction

N = mg

Thus

$f = \mu_{k}mg$ (1)

Also,

$fs = ML_{f}$ (2)

where

$L_{f} = 3.33\times 10^{5}\ J/kg$ = Latent Heat of fusion

Thus from eqn (1) and (2):

$s = \frac{ML_{f}}{\mu_{k}mg}$

$s = \frac{5\times 3.33\times 10^{5}}{0.50\times 64\times 9.8}$

s = 5.309 km

5 0

3 years ago

A 0.74 mF capacitor is connected to a standard outlet (rms voltage 82 V, frequency 49 Hz ). Determine the magnitude of the curre

disa [49]

Answer:

I = 26.36 cosω t A

Explanation:

Given that

C=0.74 mF

Vrms= 82 V

Frequency ,f= 49 Hz

We know that ω = 2 π f

ω = 2 x π x 49

ω = 307.72 rad/s

As we know that voltage given as

V= Vo sinω t

$V_o=\sqrt2\ V_{rms}$

$V_o=\sqrt2\ \times 82$ \

Vo=115.96 V

V=115.96 sinω t

The current given as

$I=C\dfrac{dV}{dt}$

$I=0.74\times \dfrac{dV}{dt}\ mA$

$\dfrac{dV}{dt}=115.96\omega cos\omega t$

$I=0.74\times 115.96\times 307.22 cos\omega t\ mA$

I = 26362.67 cosω t mA

I = 26.36 cosω t A

This is the current at time ant time t.

7 0

3 years ago

2. If a rock fell down a cliff and hit the bottom of the ravine at 4 seconds, how fast was the rock

Iteru [2.4K]

Answer: -39.2 m/s or 39.2 m/s directed downwards

Explanation:

This situation is a good example of Free Fall, where the main condition is that the initial velocity must be zero $V_{o}=0$ , and the acceleration is constant (acceleration due gravity).

So, in order to calculate the final velocity $V$ of the rock just at the moment it hitsthe bottom of the cliff, we will use the following equation:

$V={V_{o}}^{2}+gt$

Where:

$g=-9.8 m/s^{2}$ is the acceleration due gravity (directed downwards)

$t=4 s$ is the time it takes to the rock to fall down the cliff

$V=(-9.8 m/s^{2})(4 s)$

$V=-39.2 m/s$ This is the rock's final velocity and its negative sign indicates it is directed downwards

6 0

4 years ago

Read 2 more answers

neptune is an average distance of 4.5×10^12m from the sun. Estimate the length of the Neptunian year.

Vikentia [17]

As per Kepler's third law we know that

$\frac{T_1^2}{T_2^2} = \frac{R_1^3}{R_2^3}$

now here we know that

$T_1$ = year of Neptune

$T_2$ = year of Earth

$R_1$ = distance of Neptune from Sun

$R_2$ = Distance of Earth from Sun

so now we will have

$\frac{T_1^2}{1} = \frac{(4.5 \times 10^{12})^3}{(1.5 \times 10^11)^3}$

$T_1^2 = 27000$

$T_1 = 164.3 years$

so length of year of Neptune is 164.3 years

6 0

3 years ago

A comet is traveling through space with speed 3.01 ✕ 104 m/s when it encounters an asteroid that was at rest. The comet and the

Tcecarenko [31]

Answer: $8.493(10)^{-3} m/s$

Explanation:

According to the conservation of linear momentum principle, the initial momentum $p_{i}$ (before the collision) must be equal to the final momentum $p_{f}$ (after the collision):