A 7.1 cm diameter horizontal pipe gradually narrows to 5.4 cm . When water flows through this pipe at a certain rate, the gauge
pressure in these two sections is 32.5 kPa and 20.6 kPa , respectively. What is the volume rate of flow?
1 answer:
Answer:
Q=22.6L/s
Explanation:
First you must consider the continuity equation at points 1 and 2, which indicates that both flows are of equal value, in this way you get an equation between the two flow rates.
Then you raise the Bernoulli equation taking into account that the height is the same, which makes the term h1-h2 zero.
Using the equations above to calculate one of the speeds.
Finally you find the flow by multiplying the speed by the area.
I attached procedure
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Answer:
Explanation:
mass of car, m = 1022 kg
mass of truck, M = 1620 kg
initial velocity of truck, U = 14.5 m/s
initial velocity of car, u = 0 m/s
Let the final velocity of car is v and the final velocity of truck is V.
Collision is elastic, so the coefficient of restitution, e = 1
Use conservation of momentum
initial momentum of car + initial momentum of truck = final momentum of car + final momentum of truck
m x u + M x U = m x v + M x V
0 + 1620 x 14.5 = 1022 v + 1620 V
23490 = 1022 v + 1620 V ..... (1)
Use the formula of coefficient of restitution
1 (14.5 - 0) = v - V
14.5 = v - V
V = v - 14.5 .... (2)
Put in equation (1)
23490 = 1022 v + 1620 (v - 14.5)
23490 = 1022 v + 1620 v - 23490
46980 = 2642 v
v = 17.8 m/s
Put in equation (2)
V = 17.8 - 14.5
V = 3.3 m/s
Thus, the speed of car is 17.8 m/s and the velocity of truck is 3.3 m/s after collision.