Answer:
Δ L = 2.57 x 10⁻⁵ m
Explanation:
given,
cross sectional area = 1.6 m²
Mass of column = 26600 Kg
Elastic modulus, E = 5 x 10¹⁰ N/m²
height = 7.9 m
Weight of the column = 26600 x 9.8
= 260680 N
we know,
Young's modulus=![\dfrac{stress}{strain}](https://tex.z-dn.net/?f=%5Cdfrac%7Bstress%7D%7Bstrain%7D)
stress = ![\dfrac{P}{A}](https://tex.z-dn.net/?f=%5Cdfrac%7BP%7D%7BA%7D)
= ![\dfrac{260680}{1.6}](https://tex.z-dn.net/?f=%5Cdfrac%7B260680%7D%7B1.6%7D)
= 162925
strain = ![\dfrac{\Delta L}{L}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5CDelta%20L%7D%7BL%7D)
now,
![Y = \dfrac{stress}{strain}](https://tex.z-dn.net/?f=Y%20%3D%20%5Cdfrac%7Bstress%7D%7Bstrain%7D)
![\Delta L = \dfrac{162925}{Y}\times L](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%20%5Cdfrac%7B162925%7D%7BY%7D%5Ctimes%20L)
![\Delta L = \dfrac{162925}{5 \times 10^10}\times 7.9](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%20%5Cdfrac%7B162925%7D%7B5%20%5Ctimes%2010%5E10%7D%5Ctimes%207.9)
Δ L = 2.57 x 10⁻⁵ m
The column is shortened by Δ L = 2.57 x 10⁻⁵ m
Answer:
Height, h = 50 meters.
Explanation:
Given the following data;
Mass = 20kg
Potential energy = 10,000 J
Acceleration due to gravity, g = 10m/s²
To find the height of the box;
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
![P.E = mgh](https://tex.z-dn.net/?f=%20P.E%20%3D%20mgh)
Where,
- P.E represents potential energy measured in Joules.
- m represents the mass of an object.
- g represents acceleration due to gravity measured in meters per seconds square.
- h represents the height measured in meters.
Substituting into the formula, we have;
10000 = 20*10*h
10000 = 200h
Height, h = 10000/200
Height, h = 50 meters.
Answer:
I have a screenshot of this.
Explanation: