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3 years ago

What is the answer ?

Mathematics

1 answer:

Alja [10]3 years ago

6 0

I plugged it into my calculator and I got 1,870.

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In a class experiment, Sean finds that the probability that a student plays soccer is . If the school population is 300, how man

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What is the importance of studying Geometry in our real life?

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2 years ago

A hiker walks at a speed of 3 2/5 kilometers per hour. How many kilometers will the hiker walk in 40 minutes?

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A card is picked from a standard deck of 52 cards. Determine the odds against and the odds in favor of selecting a red face card

timama [110]

<h3>The probability of picking a red face card from the deck is $(\frac{3}{26} )$ </h3><h3>The probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$ </h3>

Step-by-step explanation:

The total number of cards in the deck = 52

The total number of red( Diamond + Hearts) face cards in the given deck

= 2 Red Queens + 2 Red jacks + 2 Red kings = 6 cards

Let E : Event of picking a red face card from the deck

Now , P( any event) = $\frac{\textrm{The number of favorable observations}}{\textrm{Total number of observations}}$

So, here P(Picking a red face card) = $\frac{\textrm{The number of red face cards}}{\textrm{Total number of cards}} = (\frac{6}{52} ) = (\frac{3}{26})$

Hence, the probability of picking a red face card from the deck is $(\frac{3}{26} )$

Now, as we know P (any event NOT A) = 1 - P(any event A)

So, P(NOT Picking a red face card) = 1 - P(Picking a red face card)

$= 1 - (\frac{3}{26} ) = \frac{26-3}{26} = (\frac{23}{26})$

Hence, the probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$

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3 years ago

Assume that the total revenue received from the sale of x items is given by, R(x)equals34 ln (4 x plus 5 ), while the total c

katen-ka-za [31]

Answer:

63 units

Step-by-step explanation:

The profit function P(x) is given by the revenue function minus the cost function:

$P(x) = R(x) - C(x)\\P(x) = 34ln(x+5)-\frac{x}{2}$

The number of units sold 'x' for which the derivate of the profit function is zero, is the number of units that maximizes profit:

$P(x) = 34ln(x+5)-\frac{x}{2}\\P'(x) =0= \frac{34}{x+5}-\frac{1}{2}\\x+5=68\\x=63\ units$

The number of units that should be manufactured so that profit is maximum is 63 units.

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3 years ago