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Dovator [93]
3 years ago
13

What is the answer ?

Mathematics
1 answer:
Alja [10]3 years ago
6 0
I plugged it into my calculator and I got 1,870.
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In a class experiment, Sean finds that the probability that a student plays soccer is . If the school population is 300, how man
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It's 144

well I just got out of a test  and the answer was 144.
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What is the importance of studying Geometry in our real life?
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Geometry allows students to connect mapping objects in the classroom to real-world contexts regarding direction and place.

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A hiker walks at a speed of 3 2/5 kilometers per hour. How many kilometers will the hiker walk in 40 minutes?
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2  4/15 km

Step-by-step explanation:

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2 years ago
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A card is picked from a standard deck of 52 cards. Determine the odds against and the odds in favor of selecting a red face card
timama [110]
<h3>The probability of picking a red face card from the deck  is (\frac{3}{26} )</h3><h3>The probability of NOT picking a red face card from the deck  is (\frac{23}{26} )</h3>

Step-by-step explanation:

The total number of cards in the deck  = 52

The total number of red( Diamond + Hearts)  face cards in the given deck

= 2 Red Queens +  2 Red jacks + 2 Red kings  = 6 cards

Let E : Event of picking a red face card from the deck

Now , P( any event)  = \frac{\textrm{The number of favorable observations}}{\textrm{Total number of observations}}

So, here P(Picking a red face card)  = \frac{\textrm{The number of red face cards}}{\textrm{Total number of cards}} =  (\frac{6}{52} ) = (\frac{3}{26})

Hence, the probability of picking a red face card from the deck  is (\frac{3}{26} )

Now, as we know P (any event NOT A)  = 1 - P(any event A)

So, P(NOT Picking a red face card) = 1 - P(Picking a red face card)

= 1 - (\frac{3}{26} ) = \frac{26-3}{26}  = (\frac{23}{26})

Hence,  the probability of NOT picking a red face card from the deck  is (\frac{23}{26} )

8 0
3 years ago
Assume that the total revenue received from the sale of x items is given​ by, ​R(x)equals34 ln (4 x plus 5 )​, while the total c
katen-ka-za [31]

Answer:

63 units

Step-by-step explanation:

The profit function P(x) is given by the revenue function minus the cost function:

P(x) = R(x) - C(x)\\P(x) = 34ln(x+5)-\frac{x}{2}

The number of units sold 'x' for which the derivate of the profit function is zero, is the number of units that maximizes profit:

P(x) = 34ln(x+5)-\frac{x}{2}\\P'(x) =0= \frac{34}{x+5}-\frac{1}{2}\\x+5=68\\x=63\ units

The number of units that should be manufactured so that​ profit is maximum is 63 units.

5 0
3 years ago
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