1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Airida [17]
2 years ago
5

..........................................................................................................

Mathematics
1 answer:
Igoryamba2 years ago
8 0

Answer:

w-2 < -25

Step-by-step explanation:

"Difference" means subtraction.

Less than is the same as the symbol <

The statement can also mean that -25 is greater than w-2.

You might be interested in
The ratio of irises to The ratio of irises to roses in Nikki's garden is 2:5. She currently has 25 roses. She is planning to add
denpristay [2]
If the proportion of iris to roses in Nikki's garden is 2: 5, it means that for 25 roses: (2/5) = (10/25). Therefore to maintain the proportion by adding 20 roses: (2/5) = (18/45). The number of irises after the addition of roses will be 10 + 18 = 28 irises.
5 0
3 years ago
⚠️URGENT PLS HELPPPPP<br><br> LINKS WILL BE REPORTED
balu736 [363]
The answer is the last one
6 0
2 years ago
suppose a farmer has six cows and each cow has six calves the first year, they all increase in the same propotion, to the end of
Sergio [31]

Hi!

To solve this question you need to solve 7^8 x 6

7^8 = 5,764,801

5,764,801 x 6 = 34,588,806

4 0
2 years ago
2. The time between engine failures for a 2-1/2-ton truck used by the military is
OLEGan [10]

Answer:

A truck "<em>will be able to travel a total distance of over 5000 miles without an engine failure</em>" with a probability of 0.89435 or about 89.435%.

For a sample of 12 trucks, its average time-between-failures of 5000 miles or more is 0.9999925 or practically 1.

Step-by-step explanation:

We have here a <em>random variable</em> <em>normally distributed</em> (the time between engine failures). According to this, most values are around the mean of the distribution and less are far from it considering both extremes of the distribution.

The <em>normal distribution</em> is defined by two parameters: the population mean and the population standard deviation, and we have each of them:

\\ \mu = 6000 miles.

\\ \sigma = 800 miles.

To find the probabilities asked in the question, we need to follow the next concepts and steps:

  1. We will use the concept of the <em>standard normal distribution</em>, which has a mean = 0, and a standard deviation = 1. Why? With this distribution, we can easily find the probabilities of any normally distributed data, after obtaining the corresponding <em>z-score</em>.
  2. A z-score is a kind of <em>standardized value</em> which tells us the <em>distance of a raw score from the mean in standard deviation units</em>. The formula for it is: \\ z = \frac{x - \mu}{\sigma}. Where <em>x</em> is the value for the raw score (in this case x = 5000 miles).
  3. The values for probabilities for the standard normal distribution are tabulated in the <em>standard normal table</em> (available in Statistics books and on the Internet). We will use the <em>cumulative standard normal table</em> (see below).

With this information, we can solve the first part of the question.

The chance that a truck will be able to travel a total distance of over 5000 miles without an engine failure

We can "translate" the former mathematically as:

\\ P(x>5000) miles.

The z-score for x = 5000 miles is:

\\ z = \frac{5000 - 6000}{800}

\\ z = \frac{-1000}{800}

\\ z = -1.25

This value of z is negative, and it tells us that the raw score is 1.25 standard deviations <em>below</em> the population mean. Most standard normal tables are made using positive values for z. However, since the normal distribution is symmetrical, we can use the following formula to overcome this:

\\ P(z

So

\\ P(z

Consulting a standard normal table available on the Internet, we have

\\ P(z

Then

\\ P(z1.25)

\\ P(z1.25)

However, this value is for P(z<-1.25), and we need to find the probability P(z>-1.25) = P(x>5000) (Remember that we standardized x to z, but the probabilities are the same).

In this way, we have

\\ P(z>-1.25) = 1 - P(z

That is, the complement of P(z<-1.25) is P(z>-1.25) = P(x>5000). Thus:

\\ P(z>-1.25) = 1 - 0.10565

\\ P(z>-1.25) = 0.89435  

In words, a truck "<em>will be able to travel a total distance of over 5000 miles without an engine failure</em>" with a probability of 0.89435 or about 89.435%.

We can see the former probability in the graph below.  

The chance that a fleet of a dozen trucks will have an average time-between-failures of 5000 miles or more

We are asked here for a sample of <em>12 trucks</em>, and this is a problem of <em>the sampling distribution of the means</em>.

In this case, we have samples from a <em>normally distributed data</em>, then, the sample means are also normally distributed. Mathematically:

\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})

In words, the samples means are normally distributed with the same mean of the population mean \\ \mu, but with a standard deviation \\ \frac{\sigma}{\sqrt{n}}.

We have also a standardized variable that follows a standard normal distribution (mean = 0, standard deviation = 1), and we use it to find the probability in question. That is

\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ z \sim N(0, 1)

Then

The "average time-between-failures of 5000" is \\ \overline{x} = 5000. In other words, this is the mean of the sample of the 12 trucks.

Thus

\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ z = \frac{5000 - 6000}{\frac{800}{\sqrt{12}}}

\\ z = \frac{-1000}{\frac{800}{\sqrt{12}}}

\\ z = \frac{-1000}{230.940148}

\\ z = -4.330126

This value is so low for z, that it tells us that P(z>-4.33) is almost 1, in other words it is almost certain that for a sample of 12 trucks, its average time-between-failures of 5000 miles or more is almost 1.

\\ P(z

\\ P(z

\\ P(z

The complement of P(z<-4.33) is:

\\ P(z>-4.33) = 1 - P(z or practically 1.

In conclusion, for a sample of 12 trucks, its average time-between-failures of 5000 miles or more is 0.9999925 or practically 1.

7 0
2 years ago
2/3 / (-9/4)<br><br> 2/3 divided by (-9/4)
Bezzdna [24]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

\frac{2}{3}  \div ( -  \frac{9}{4} ) =  \\

\frac{2}{3}  \times( -   \frac{4}{9}) =  \\

-  \frac{2 \times 4}{3 \times 9}  =  -  \frac{8}{27}  =  -  ({ \frac{2}{3} })^{3}  \\

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

8 0
2 years ago
Other questions:
  • Two basketball players average the same number of points per game. What information would be most helpful in determining which p
    11·2 answers
  • Which function transforms the graph of y=x^2 so that it is first shifted down 4 units and is then reflected across the y-axis?
    11·1 answer
  • Which of the following best describes the equation below y=5x+6
    13·1 answer
  • The table shows the number of cakes and pies that Gretchen sold at the bake sale last weekend
    8·2 answers
  • It takes a graphic designer 1.5h to make one page of a website. Using a new software, the designer could complete each page in 1
    6·2 answers
  • b) Suppose that s equals the number of stones on one side of the picture frame. Write an expression that would give the number o
    11·1 answer
  • A complex electronic system is built with a certain number of backup components in its subsystems. One subsystem has four identi
    6·1 answer
  • 1. write it on a piece of paper
    10·2 answers
  • What values does the function f of x is equal to the square root of the quantity x plus 1 end quantity minus 3 have in its range
    15·1 answer
  • At what point does y = 2x + 3 intercept: a) The y-axis: b) The x-axis:​
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!