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Olegator [25]
2 years ago
8

Which inequalities is -5 a possible solution?

Mathematics
1 answer:
coldgirl [10]2 years ago
5 0

Answer:

1st, 3rd and second last one

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I need help with this one as well. I got the last where you plug the number in and solve for y
Kobotan [32]
X=2→F(2)=[(2)^3+3]/[(2)^2-5]
F(2)=(8+3)/(4-5)
F(2)=11/(-1)
F(2)=-11

-2/F(2)=-2/(-11)
-2/F(2)=2/11

Answer: 2/11
4 0
3 years ago
How do you simplify this problem
vampirchik [111]
Reduce the fraction with 2
\frac{2 \times x {}^{ - 2} y {}^{3}z {}^{ - 1}  }{xy}  \\  \\  \frac{3y {}^{2}z {}^{ - 1}  }{x {}^{3} }  \\  \\  \frac{3y {}^{2} }{x {}^{3}   z}
7 0
3 years ago
Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?
gladu [14]
Sum:

     3x^5*y - 2x^3*y^4 - 7x*y^3
 + -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
     -5x^5y - 6xy^3

Term 1: Degree = 6
Term 2: Degree = 4

Difference:

     3x^5*y - 2x^3*y^4 - 7x*y^3
 -  -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
     11x^5y - 4<span>x^3*y^4 - 8</span>xy^3

Term 1: Degree = 6
Term 2: Degree = 7
Term 3: Degree = 4

The degree of a term of a polynomial can be obtained by adding the exponents of the variables in that term.
5 0
3 years ago
I am a solid figure with two congruent polygons that are bases connected with lateral faces that are rectangles
Delvig [45]
The shape is a prism
5 0
3 years ago
Solve: 2(x - 5) &lt; -6(1 - x)
Marizza181 [45]

Answer:

B. x > -1

Step-by-step explanation:

Subtract the left side:

... 0 < -6(1 -x) -2(x-5)

... 0 < -6 +6x -2x +10 . . . . eliminate parentheses

... 0 < 4 +4x . . . . . . . . . . . collect terms

... 0 < 1 +x . . . . . . . . . . . . . divide by 4

... -1 < x . . . . . . . . . . . . . . . add -1. Matches selection B.

4 0
3 years ago
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