To make it quickly we can consider only those numbers which will give us a decimal of xxx.7. There are only a few numbers like this: 85.2, 88.2, 20.5.

I tried adding 85.2 to 17.5 and it gave me 102.5 - it was close but not close enough :)

So I picked 85.2 + 20.5 = 105.7 and voila :)

6 0

3 years ago

A consumer advocate wants to collect a sample of jelly jars and measure the actual weight of the product in the container. He ne

Ivahew [28]

Answer:

n=3.8416≅4

So Minimum Sample Size is 4

Step-by-step explanation:

In order to find the minimum sample size, the formula we use will be:

$n= \frac{Z^2*S^2}{E^2}$

Where:

n is sample size

Z is the distribution

S is the standard deviation

E is the Margin of error

S=3 ,E=3

For Z:

Alpha=1-0.95=0.05

Alpha/2=0.025=2.5%

From Cumulative Standard Distribution Table:

Z at Alpha/2 = 1.960

$n= \frac{1.960^2*3^2}{3^2}$

n=3.8416≅4

So Minimum Sample Size is 4

8 0

3 years ago