Answer is 28
y+z=4 => y=4-z
yz=3 => (4-z)z=3
=> z^2-4z+3=0
=> z=1 y=3 OR z=3 y=1
=>y^3 + z^3 =3^3+1=28
First, write an equation system based on the problem
An equation for "the perimeter of a rectangle is 70 in" can be written as following
∴ 2l + 2w = 70 <em>(first equation)</em>
An equation for "the length is 11 in more than its width" can be written as following
∴ l = w + 11 <em>(second equation)</em>
Second, solve the equation by substitution method o find the dimension of the rectangle.
Substitute/plug l as (w+11) into the first equation
2l + 2w = 70
2(w + 11) + 2w = 70
2w + 22 + 2w = 70
4w + 22 = 70
4w = 70 - 22
4w = 48
w = 48/4
w = 12
The width of the rectangle is 12 in
Substitute w with 12 to the second equation
l = w + 11
l = 12 + 11
l = 23
The length of the rectangle is 23 in
Third, find the area of the rectangle
a = l × w
a = 23 × 12
a = 276
The area of the rectangle is 276 in²
Answer:
I think its 10 pls dont get mad at me if its wrong.
Step-by-step explanation:
if you see x and then 10 you can see they line up
Hi there!
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I believe your answer is:
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Here’s why:
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Hope this helps you. I apologize if it’s incorrect.
1) 200 + 400 = 600
200/600 = 1/3
1/3 X 100 = 33%
200 = 33%
400 = 66 % (C)
2) 100/500 = 1/5
1/5 X 100 = 20% (C)
Let me know if you need help understanding it :)