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alex41 [277]
3 years ago
15

What is the probability of rolling double six

Mathematics
2 answers:
Vanyuwa [196]3 years ago
5 0
The odds of rolling a five with one die are 1 in 6; the dice are independent so the odds of rolling another five are 1 in 6; therefore the odds of rolling double fives are.
$$(1/6)*(1/6<span>) = </span>1/36$$.
1 in 36.
<span>By this logic, our new player just did something pretty unlikely on her first roll. this is the answer i think </span>
coldgirl [10]3 years ago
4 0
1/36
a 6 on a die is only on one face, so that would be 1/6 of the whole die
to roll a double would mean take 1/6 x 1/6
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A spaceship is traveling at a steady rate. The table shows the distance the spaceship travels in a given period of time. Find th
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The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.

<h3>What is the distance the spaceship travels in 4 minutes?</h3>

The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;

Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.

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The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly sel
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Complete question:

The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly selects 45 customers and records the amount of time from the moment they stand in the back of a line until the moment the cashier scans their first item. He calculates the mean and standard deviation of this sample to be barx = 4.2 minutes and s = 2.0 minutes. If appropriate, find a 90% confidence interval for the true mean time (in minutes) that customers at this supermarket wait in a check-out line

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(3.699, 4.701)

Step-by-step explanation:

Given:

Sample size, n = 45

Sample mean, x' = 4.2

Standard deviation \sigma = 2.0

Required:

Find a 90% CI for true mean time

First find standard error using the formula:

S.E = \frac{\sigma}{\sqrt{n}}

= \frac{2}{\sqrt{45}}

= \frac{2}{6.7082}

SE = 0.298

Standard error = 0.298

Degrees of freedom, df = n - 1 = 45 - 1 = 44

To find t at 90% CI,df = 44:

Level of Significance α= 100% - 90% = 10% = 0.10

t_\alpha_/_2_, _d_f = t_0_._0_5_, _d_f_=_4_4 = 1.6802

Find margin of error using the formula:

M.E = S.E * t

M.E = 0.298 * 1.6802

M.E = 0.500938 ≈ 0.5009

Margin of error = 0.5009

Thus, 90% CI = sample mean ± Margin of error

Lower limit = 4.2 - 0.5009 = 3.699

Upper limit = 4.2 + 0.5009 = 4.7009 ≈ 4.701

Confidence Interval = (3.699, 4.701)

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