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Katarina [22]
3 years ago
8

Help me for 1 through 6 pls I WANT TO FINISH ON TIME THANKS YOU

Mathematics
1 answer:
umka2103 [35]3 years ago
4 0
1) put a bar over the last 4
2) put a bar over the last 3 numbers (198)
3) Put a bar over the last 2 numbers (39)
4)0.818181
5)0.199999
6)0.36743674

hope this helps
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Which three-dimensional object is formed when the shape is rotated about the axis as shown?
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A football player kicks a 0.94 kg football with a force of 2.4n. Calculate the acceleration of the football as the player kicks
Setler [38]

Answer:

2.6 meters per seconds squared

Step-by-step explanation:

We can use the formula   F = MA  to solve this problem.

F is the force (in Newtons)

M is the mass (in Kgs)

A is the acceleration in m/s^2

The force (F) is given as 2.4 newtons and mass (M) is given as 0.94 kgs, so we substitute into the formula and solve for acceleration (A):

F = MA

2.4 =  0.94(A)

A= 2.4/0.94 = 2.55 m/s^2

<em>rounding to nearest tenth, we have </em><em>acceleration = 2.6 m/s^2</em>

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3 years ago
the sales tax in your city is 4.4% and an item costs 3$ before tax how much tax will you pay on that item
Mashcka [7]

Answer:

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Step-by-step explanation:

3 x 1.044 = 3.132

3 0
3 years ago
(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
What is 4 plus 4?12234
RideAnS [48]

Answer:

sadada

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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