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3 years ago

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The sides of a rectangle are a number and 4 less than that same numbers. The perimeter is 56. Find the dimensions of the rectang

le. write an algebraic expression or equation to represent the verbal expression.

1 answer:

Rzqust [24]3 years ago

8 0

Answer: find the answer in the explanation.

Step-by-step explanation:

You are given that the sides of a rectangle are a number and 4 less than that same numbers.

Let the length side = L

And width side = L - 4

The dimensions of the rectangle will be

Area = length × width

L × ( L - 4 )

Open the bracket

L^2 - 4L

The verbal expression here,

Perimeter = L + L + W + W

Substitute all the parameters into the formula

56 = L + L + L-4 + L-4

56 = 2L + 2L - 8

56 = 4L - 8

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How much faster does Student B read than Student A?

Romashka-Z-Leto [24]

Answer:

He reads faster by 8 pages.

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3 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

so

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

so

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago

Y= -2(x - 1)^2 + 8 the answer

Dahasolnce [82]

Y = (-2x +2)^2 +8
(-2x^2 +4) +8
-2x^2 +12

8 0

3 years ago

A forester wishes to predict the volume (in cubic feet) of usable lumber in a certain species of tree using the height (in feet)

alex41 [277]

Answer: The response variable = Volume

and explanatory variable(s) in this study are: Height and Diameter.

Step-by-step explanation:

Important definitions:

The explanatory variable is a type of independent variable manipulated by the experimenter for the ongoing experimental study.
The response variable is a type of dependent variable which depends on the explanatory values provided by the experimenter.

Given: A forester wishes to predict the volume (in cubic feet) of usable lumber in a certain species of tree using the height (in feet) and diameter (in inches) of the trees.

Here, Volume directly depends upon the height and diameter of the tree.

Also, forester ( Experimenter) wants to predict volume by cutting tree that means it is an response variable and it depends on height and diameter , so height and diameter are explanatory variable.

Hence, The response variable = Volume

and explanatory variable(s) in this study are: Height and Diameter.

7 0

3 years ago

Which is the following points is NOT a solution to the inequality y > - x + 3? —a. ( -2,6)b. (5,-1)c. (2,0)d. (0,3)

CaHeK987 [17]

Given -

y > - x + 3

To Find -

The points which is NOT a solution to the inequality

Step-by-Step Explanation -

We will put the value of each in inequality and then see if it satisfies the given condition or not.

a. ( -2,6)

So, x = -2 and y = 6 in y > - x + 3

= 6 > - (-2) + 3

= 6 > 5 (Correct Solution)

b. (5,-1)

So, x = 5 and y = -1 in y > - x + 3

= -1 > -5 + 3

= -1 > -2 (Correct Solution)

c. (2,0)

So, x = 2 and y = 0 in y > - x + 3

= 0 > -2 + 3

= 0 > 1 (Incorrect Solution)

d. (0,3)

So, x = 0 and y = 3 in y > - x + 3

= 3 > -0 + 3

= 3 > 3 (Incorrect Solution)

Final Answer -

The points which is NOT a solution to the inequality =

c. (2,0)

d. (0,3)

3 0

1 year ago