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saw5 [17]
3 years ago
12

The sides of a rectangle are a number and 4 less than that same numbers. The perimeter is 56. Find the dimensions of the rectang

le. write an algebraic expression or equation to represent the verbal expression.
Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer: find the answer in the explanation.

Step-by-step explanation:

You are given that the sides of a rectangle are a number and 4 less than that same numbers.

Let the length side = L

And width side = L - 4

The dimensions of the rectangle will be

Area = length × width

L × ( L - 4 )

Open the bracket

L^2 - 4L

The verbal expression here,

Perimeter = L + L + W + W

Substitute all the parameters into the formula

56 = L + L + L-4 + L-4

56 = 2L + 2L - 8

56 = 4L - 8

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Step-by-step explanation: It's a straight line to the alienbecause it's straight down the x-axis

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Bananas cost $0.54 per pound and grapes cost $1.28 per pound. Leanne bought 2.6 pounds of bananas and 3.1 pounds of grapes. How
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.52*2.6=1.40


1.28*3.1= 3.97

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3 years ago
We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely. (a) Given that the roll results
boyakko [2]

Answer:

a) \frac{1}{7}

b) \frac{2}{15}

Step-by-step explanation:

Given : We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely.

The outcomes are :

(1, 1) (1, 2)  (1, 3)  (1, 4)  (1, 5)  (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

(a) Given that the roll results in a sum of 3 or more, find the conditional probability that doubles (the first and the second rolls result in the same number) are rolled.

Let P(A) be the probability of event that the roll results in a sum of 3 or more.

Except (1,1) rest sum is 3 or greater than 3.

So, P(A)=\frac{35}{36}

Now, P(A and B) is that the roll results in a sum of 3 or more and that doubles (the first and the second rolls result in the same number) are rolled.

i.e. (2,2), (3,3), (4,4), (5,5), (6,6) - 5

P(A\cap B)=\frac{5}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{5}{36}}{\frac{35}{36}}

P(B|A)=\frac{5}{35}

P(B|A)=\frac{1}{7}

(b) Given that the two dice land on different numbers, find the conditional probability that the sum is 5.

Let P(A) be the probability of event that two dice land on different numbers.

Except (1,1),(2,2), (3,3), (4,4), (5,5), (6,6) rest two dice land on different numbers.

So, P(A)=\frac{30}{36}

Now, P(A and B) is that two dice land on different numbers and the sum is 5.

i.e. (1,4), (2,3), (3,2), (4,1) - 4

P(A\cap B)=\frac{4}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{4}{36}}{\frac{30}{36}}

P(B|A)=\frac{4}{30}

P(B|A)=\frac{2}{15}

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