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Nuetrik [128]
3 years ago
12

Shannon biked in an endurance cycling race.She traveled 2,912 miles and biked about 95 miles each day.About how many days did it

take her to complete the race?
Mathematics
2 answers:
REY [17]3 years ago
7 0
About 31 days for her to complete the race
AlekseyPX3 years ago
6 0

Answer:

About 31 days

Step-by-step explanation:

We are given that

Distance traveled by Shannon=2,912 miles

She travels distance per day=About 95 miles

We have to find  number of days taken by Shannon to complete the race.

To find the number of days taken by Shannon to complete the race we will find the time taken by Shannon to complete 1 mile distance

Shannon takes time to cover  about 95 miles distance=1 day

Shannon takes time to cover  1 mile distance=\frac{1}{95} day

Shannon takes time to cover  2,912 miles distance =\frac{1}{95}\times 2,912

Shannon takes time to cover  2,912 miles distance=30.65 days\approx 31 days.

Hence, Shannon takes time to complete the race=about 31 days

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Evaluate the expression
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12-[20-2(6^2\div3\times2^2)]=88

Step-by-step explanation:

So we have the expression:

12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

Square the 6 and the 4:

(36\div3\times4)

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

(36\div3\times4)\\=(12\times4)\\=48

Therefore, the original equation is now:

12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]

Multiply with the brackets:

=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

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Step-by-step explanation:

X=y-5

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Substituting the value of y

8-5=x

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