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Nuetrik [128]
3 years ago
12

Shannon biked in an endurance cycling race.She traveled 2,912 miles and biked about 95 miles each day.About how many days did it

take her to complete the race?
Mathematics
2 answers:
REY [17]3 years ago
7 0
About 31 days for her to complete the race
AlekseyPX3 years ago
6 0

Answer:

About 31 days

Step-by-step explanation:

We are given that

Distance traveled by Shannon=2,912 miles

She travels distance per day=About 95 miles

We have to find  number of days taken by Shannon to complete the race.

To find the number of days taken by Shannon to complete the race we will find the time taken by Shannon to complete 1 mile distance

Shannon takes time to cover  about 95 miles distance=1 day

Shannon takes time to cover  1 mile distance=\frac{1}{95} day

Shannon takes time to cover  2,912 miles distance =\frac{1}{95}\times 2,912

Shannon takes time to cover  2,912 miles distance=30.65 days\approx 31 days.

Hence, Shannon takes time to complete the race=about 31 days

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I need help with a math question
Julli [10]

Answer:

Question 1: 4.5(10^−7)(2(10^4))

=

9/1000

(Decimal: 0.009)

Question 2:

mass of neutron/mass of electron = 2*10-24/(9*10-28)

2x10^(-24)/9x10^(-28)

d is closest.

Question 3:

4(10^3)(12(10^5))

=4000*1200000

=4*1000*12*100000

=(4*12)*(1000*100000)

=48*100000000

=4800000000

And these things : ^ mean raising the number to become exponets and when I put the number into a bold text thats the answer!

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3 0
3 years ago
This figure is made up of a quadrilateral and a semicircle.
Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}

The length of AD is

AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}

Since AB=AD, therefore ABCD is a square. The area of the of square is

A_1=a\times a=\sqrt{29}\times \sqrt{29} =29

The area of square is 29 units².

The area of a semicircle is

A_2=\frac{\pi}{2}r^2

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

r=\frac{d}{2}=\frac{\sqrt{29}}{2}

The area of the semicircle is

A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825

The area of the figure is

A=A_1+A_2=29+11.2825=40.3825\approx 40.4

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0
3 years ago
You have 4 cards, 2 black and 2 red. You play a game where during each round you draw a card. If it's black, you lose a point. I
sineoko [7]

Answer: The expected value of this game is 2/3

Step-by-step explanation:

Give that

If it's black, you lose a point. If it's red, you gain a point. 

And then you can stop at any time. But you should never stop when you are losing because that can guarantee 0 by drawing all the cards.

Assuming you should stop after three cards when you are +2.

The only question is whether to draw if you are +1 on the first draw.

If you draw red first, You have 1/3 chance of drawing red again and this will give you +2 points

1/3 chance of drawing two blacks and earn zero point, chance of drawing black-red and earn +1. This gives +1, so it doesn't matter whether you draw or not.

From the beginning, If you draw red (probability 1/2 you end +1. If you draw black and then draw two reds (probability 1/6 you end +1) Otherwise you break even with probability 1/3. Overall, the value is 2/3

8 0
3 years ago
3a+2b=193<br><br> Find a and b
galina1969 [7]
Hope this made sense

6 0
3 years ago
Help please im lost and not good in math
Damm [24]
Answers: a = 49
b = 10
c = 105
8 0
3 years ago
Read 2 more answers
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