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Maurinko [17]
3 years ago
9

Is (1, 2) a solution of 6x-y > 3?

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

6(1)-2>3

6-2>3

4>3

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A recipe calls for 1/4 cup of apples and 3/8 cup of peaches. how many total fruit will Be used it the recipe. (I'm to lazy to tr
Zina [86]

Answer:

5/8

Step-by-step explanation:

1/4 (2/2)=2/8

3/8 (already simplified)

2/8+3/8=5/8

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2 years ago
A point P moves such that it is three units from the point (3, 4). Obtain the
Softa [21]
The right answer is y=-3
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3 years ago
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(2x+4)^2 - (x-5)^2 = 26x<br> Please solve (explained)
Zina [86]

Expand the squared binomials:

(2x+4)^2=4x^2+16x+16

(x-5)^2=x^2-10x+25

Then

(4x^2+16x+16)-(x^2-10x+25)=3x^2+26x-9=26x

\implies3x^2-9=0

\implies3x^2=9

\implies x^2=3

\implies x=\pm\sqrt3

5 0
3 years ago
Pls someone answer pls :)
Goshia [24]

Answer:

(-x-2) (-2x -3)=0

=>[-(x +2)] [-(2x+3)]=0

=>(x + 2)(2x +3)=0

=>x =-2 or,x=-3/2

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3 0
3 years ago
Read 2 more answers
WILL mark brainliest!
Angelina_Jolie [31]

Answer:

  110.5348 minutes

Step-by-step explanation:

The difference from room temperature changes from 103 to 59 in 46 minutes, so that difference can be modeled by the exponential equation ...

  Δt = 103×(59/103)^(t/46)

We want to find t for the temperature difference Δt = 91 -64 = 27.

  27 = 103×(59/103)^(t/46)

  27/103 = (59/103)^(t/46) . . . . . divide by 103

Taking logs gives the linear equation ...

  log(27/103) = (t/46)log(59/103)

Multiplying by the inverse of the coefficient of t, we get ...

  t = 46·log(27/103)/log(59/103) ≈ 46·(-0.58147346)/(-0.24198521)

  ≈ 110.5347

It will take about 110.5347 minutes for the turkey to cool to 91 °F internally.

_____

<em>Comment on 4 decimal places</em>

An answer correct to 4 decimal places (7 significant digits) is a pretty good indication that the problem was worked correctly. However, that level of precision in the timing makes little sense in this context. Most thermometers will take at least a few seconds to register the temperature to within a tenth of a degree or so. This problem is asking for an answer that is within 6 milliseconds and 30 micro-degrees. Neither of these is anywhere near realistic for a kitchen meat thermometer.

More realistic would be an answer to 4 <em>significant figures</em>, a tenth of a minute and a few hundredths of a degree.

(The rate of change at the time of interest is about -0.33 degrees per minute.)

6 0
3 years ago
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