<span>Assume 11^10 - 1 = 0 (mod 100) (i.e. 11^10 - 1 is divisible by 100).
11^10 - 1 = 0 (mod 100)
11^10 = 1 (mod 100)
(11^2)^5 = 1 (mod 100)
(121)^5 = 1 (mod 100)
(21)^5 = 1 (mod 100) [the remainder of 121 divided by 100 is 21]
(21^2)^2(21) = 1 (mod 100)
(41)^2(21) = 1 (mod 100)
81(21) = 1 (mod 100)
1701 = 1 (mod 100)
∴ 11^10 - 1 is divisible by 100.</span>
Answer:
The voume of the cylinder is (pi)(x^2)(y)
Voulne of the cone is (1/3)(pi)(3x)^2(h). H is the unknown height of the con2
Since the volumes are equal
(pi)(x^2)y = (1/3)(pi)(9x^2)h
h= y/3
Step-by-step explanation:
For the answer to the question above,
the given area of triangle, whose h = 6b +1 is equal 13 square feet
if the base is x which equation models the area
A = x*h/2
13 = x*(6x+1)/2
26 = 6x^2 +x
the equation which models area will be 6x^2 +x -26 =0
I hope my answer helped you.
Answer:
2*base area+l.s.a
Step-by-step explanation:
2*(l*w)+lw+lh+lw