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ikadub [295]
3 years ago
13

There are five marbles in a bag: four are blue, and one is red. What is the probability that blue Marble gets picked?

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0

Probability of picking blue marble = \frac{4}{5}

Step-by-step explanation:

Given,

Number of blue marbles = 4

Number of red marble = 1

Total number of marbles = 5

To find the probability of picking blue marble

Formula

Probability of an event = (number of occurrence of an event) ÷ (total number of events)

So,

Probability of picking blue marble = \frac{4}{5}

astraxan [27]3 years ago
6 0

Answer:

4/5 or 80%

Step-by-step explanation:

4 out of 5 marbles are blue and 4/5 = .8

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What is the answer to this problem?
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Surface area = 24in

Step-by-step explanation:

I think its 6in x 4in

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5 0
3 years ago
The average breaking strength of a certain brand of steel cable is 2000 pounds, with a standard deviation of 100 pounds. A sampl
Westkost [7]

Answer:

1963.2 pounds (lbs.)

Step-by-step explanation:

Things to understand before solving:

  • - <u>Normal Probability Distribution</u>
  1. The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by: Z=\frac{X-u}{a}

The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.

  • - <u>Central Limit Theorem</u>
  1. The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц  and standard deviation s=\frac{a}{\sqrt{n} }

As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.

This means, ц  = 2000 and б = 100.

A random sample of 20 cables is chosen and tested.

This means that n = 20, s=\frac{100}{\sqrt{120} } =22.361

Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.

This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So Z=\frac{X-u}{a}

  • By the Central Limit Theorem

Z=\frac{X-u}{a} \\-1.645=\frac{X-2000}{22.361} \\X-2000=-1.645*22.361

X =1963.2

<h3>Answer:</h3>

The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.

3 0
3 years ago
What is 2 3/8 as a percent
Maru [420]
Percent means parts out of 100 so x%=x/100
convert to improper fraction for in x/y form so

2 and 3/8
2=16/8
2 and 3/8=16/8+3/8=19/8
convert bottom number to 100
one way is multiply whole thing by 100/100
19/8 times 100/100=1900/800
divide by 8
237.5/100=237.5%
that is precent
another way is divide completely
19/8=2.375
that is over 1 so convert to over 100 so
2.375/1 times 100/100=237.5/100=237.5%

answe ris 237.5%
6 0
3 years ago
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