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3 years ago

What’s the prime factor** of 630

Mathematics

1 answer:

Travka [436]3 years ago

8 0

Answer:

Positive Integer factors of 630 = 2, 3, 6, 18, 5, 90, 7, 630 divided by 2, 3, 3, 5, 7, gives no remainder. They are integers and prime numbers of 630, they are also called composite number.

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Natali [406]

The correct answer is: 
green and blue.

Explanation: 
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We can divide fractions to determine if $\frac{3}{4}$ is a multiple of $\frac{1}{2}$ :
$\frac{ \frac{3}{4}}{ \frac{1}{2}}$ ;

in order to divide fractions, flip the second one and multiply:
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flip the second one and multiply:
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6 0

3 years ago

Read 2 more answers

Does 23^-1 (mod 1000) exist? If yes solve it.

sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let x be the inverse. Then x is such that

23x ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for x :

1000 = 43×23 + 11

23 = 2×11 + 1

→ 1 ≡ 23 - 2×11 (mod 1000)

→ 1 ≡ 23 - 2×(1000 - 43×23) (mod 1000)

→ 1 ≡ 23 - 2×1000 + 86×23 (mod 1000)

→ 1 ≡ 87×23 - 2×1000 ≡ 87×23 (mod 1000)

→ 23⁻¹ ≡ 87 (mod 1000)

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Answer:

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3 years ago

Please Help..........

Troyanec [42]

Your answer should be 31
Tell me if it was correct?
Thanks!

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