Question

2. Cement has a density of 3.0 g/cm3. You must pour a cement walkway with the

Answer 1

For this case we have to by definition:

$d = \frac {M} {V}$

Where:

d: It is the density

M: It's the mass

V: It is the volume

According to the data we have to:

$d = 3.0 \frac {g} {cm ^ 3}$

On the other hand we have that 1 meter is equivalent to 100 centimeters. Thus the measurements of the walkway are:

600 cm long, 100 cm wide and 10 cm thick. Looking for the volume we have:

$V = 600 * 100 * 10\\V = 600,000 cm ^ 3$

According to the formula we have:

$M = d * V\\M = 3.0 \frac {g} {cm ^ 3} * 600,000 cm ^ 3\\M = 1,800,000g$

Thus, the mass of the walkway is 1,800,000g

Answer:

1,800,000g