Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=

a=-0.04
b=8.3
c=4.3
x=

x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
Answer:
Step-by-step explanation:
Answer:
rate of change = -32 feet/second
Step-by-step explanation:
h(t) = 64 – 16t2
t = time (seconds)
Look at the start of time where t = 0
h(t) = 64 - 16 * (0) * 2 = 64 feet
Then look at the specified time where t = 1.25 seconds
h(t) = 64 - 16 * (1.25sec) * 2 = 24 feet
rate of change = rate of change y / rate of change x
x = time, y = height
rate of change = (24 - 64) / (1.25 - 0) = -32 feet/second
Answer:
cos(
) or 0.339
Step-by-step explanation:
I believe it would be (4,5)