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3 years ago

What’s the slope of the line?

Mathematics

2 answers:

Alexeev081 [22]3 years ago

6 0

Answer:

4/3

Step-by-step explanation:

You use Rise over Run.

It runs 3 blocks to the left (+).

It rises 4 blocks up (+).

Mariulka [41]3 years ago

3 0

Answer:

is the change in y over the change in x

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Estimate the sum of 890 + 201.

Nonamiya [84]

Answer: 1091

Step-by-step explanation: add the numbers

8 0

3 years ago

Calculate the area of a rectangle with an altitude of 30cm and a diagnol of 50cm

romanna [79]

Answer:

2000cm²

Step-by-step explanation:

find the other side using pythagorean theorem

50²=30²+x²

x=40

Area = 40 * 50 = 2000cm²

7 0

3 years ago

AngleB = Round your answer to the nearest hundredth. А 5 ? B С 4.

Zarrin [17]

Answer:

$B=36.87$

Step-by-step explanation:

As we are given the adjacent (a) side and the hypotenuse (h), we can use the cosine function to find the measure of angle B.

Recall that $cos(B)=\frac{a}{h}$

This means that in order to find B, we need to take the inverse of cosine

This gives us

$B=cos^{-1} (\frac{4}{5} )$

From a calculator, we find that the answer of this is

$B=36.869$

When this is rounded to the nearest hundredth, we get

$B=36.87$

3 0

3 years ago

Simplity. 2+{8-2 [32+5(1+2)]} Enter your answer in the box.

V125BC [204]

Answer:

284

Step-by-step explanation:

You have to start out multiplying the (parentheses), then the [brackets], then the {curly brackets}. After you're done with those you would add 2.

5 0

3 years ago

Location is known to affect the number, of a particular item, sold by an automobile dealer. Two different locations, A and B, ar

yKpoI14uk [10]

Answer:

We conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Step-by-step explanation:

We are given that Location A was observed for 18 days and location B was observed for 13 days.

On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4.

Let $\mu_1$ = true mean number of sales at location A.

$\mu_2$ = true mean number of sales at location B

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2\geq0$ or $\mu_1 \geq \mu_2$ {means that the true mean number of sales at location A is greater than or equal to the true mean number of sales at location B}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2$ or $\mu_1< \mu_2$ {means that the true mean number of sales at location A is fewer than the true mean number of sales at location B}

The test statistics that would be used here Two-sample t test statistics as we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n__1_-_n__2-2$

where, $\bar X_1$ = sample average of items sold at location A = 39

$\bar X_2$ = sample average of items sold at location B = 49

$s_1$ = sample standard deviation of items sold at location A = 8

$s_2$ = sample standard deviation of items sold at location B = 4

$n_1$ = sample of days location A was observed = 18

$n_2$ = sample of days location B was observed = 13

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(18-1)\times 8^{2}+(13-1)\times 4^{2} }{18+13-2} }$ = 6.64

So, test statistics = $\frac{(39-49)-(0)}{6.64 \times \sqrt{\frac{1}{18}+\frac{1}{13} } }$ ~ $t_2_9$

= -4.14

The value of t test statistics is -4.14.

Now, at 0.01 significance level the t table gives critical value of -2.462 at 29 degree of freedom for left-tailed test.

Since our test statistics is less than the critical values of t as -2.462 > -4.14, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

3 0

3 years ago