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alexandr402 [8]
3 years ago
7

A=1/2b and 3b:4c, find a:c Can anyone help?

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

3a: 2c

Step-by-step explanation:

a= \frac{1}{2}b \\2a= b\\\\

6a = 3b\\3b : 4c \\6a :4c\\\\=\\3a : 2c

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The answer will be B. Hope it help!
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Which mixed number is equivalent to 9/7? A. 1 2/9. B. 1 2/7. C. 2 1/7 D. 2 1/9
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In mixed form, it would be equal to 1 2/7

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Write the next three multiples of 9 <br> 36,
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Answer:

45,54,63

Step-by-step explanation:

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A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
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Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

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The lower control point will be 7.72 ounces.

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The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

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P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

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There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

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P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

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