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Marta_Voda [28]
3 years ago
6

Multiply the following complex numbers (4-6i)(6-8i)

Mathematics
2 answers:
Bad White [126]3 years ago
6 0
(4-6i)(6-8i)

24-32i-36i+48i²

24 + -68i - 48

-24-68i
iragen [17]3 years ago
4 0
4*6=24
4*(-8i)=-32i
-6i*6=-36i
-6i*(-8i)=(-6*-8)(i*i)=(48)(-1)=-48
(4-6i)(6-8i)=
-24-68i
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