Question

What is 5x-4y=-7 (-20,-8)in slope intercept form

Answer 1

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following equation:

$5x-4y = -7$

We manipulate algebraically to write the equation of the slope-intersection form:

$-4y = -7-5x\\4y = 5x + 7\\y = \frac {5} {4} x + \frac {7} {4}$

We check if the given point belongs to the equation:

$y = \frac {5} {4} (- 20) + \frac {7} {4}\\y = -25 + \frac {7} {4}\\y = \frac {-100 + 7} {4}\\y = - \frac {93} {4}$

The point does not belong to the equation.

ANswer:

$y = \frac {5} {4} x + \frac {7} {4}$