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2 years ago

Solution to the inequality −13 > −5x + 2 > −28

1 answer:

4 0

- 13 > -5x + 2 > -28.....subtract 2
-13 - 2 > -5x + 2 - 2 > -28 - 2
-15 > -5x > -30....divide by -5. and change inequality sign
-15/-5 < (-5/-5)x < -30/-5
3 < x < 6

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What is the smallest degree of rotation that will map a regular 18 gon on to itself

natali 33 [55]

Answer:

20°

Step-by-step explanation:

Rotating the figure through an angle equal to the central angle of one "sector" will do the required mapping. That is 360°/18 = 20°.

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3 years ago

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Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

<u>Area of triangle ABD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

<u>Area of triangle BCD</u>

Observing the graph

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$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

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$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

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3 years ago

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andreyandreev [35.5K]

Answer:

Step-by-step explanation:

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ale4655 [162]

Answer:

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