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Marrrta [24]
3 years ago
14

Juanita begins to factor an expression as shown. x2 + 3x – 18 = (x + )(x – ) The numbers that should be placed in the boxes, fro

m left to right, are 3 and 62 and 96 and 39 and 2
Mathematics
2 answers:
zaharov [31]3 years ago
7 0

Answer:

The correct option is 3.

Step-by-step explanation:

Let the missing values from left to right are a and b.

The given equation is

x^2+3x-18=(x+a)(x-b)

Splitting the middle term we get

x^2+6x-3x-18=(x+a)(x-b)

(x^2+6x)-(3x-18)=(x+a)(x-b)

Taking out common factors from each parenthesis.

x(x+6)-3(x+6)=(x+a)(x-b)

(x+6)(x-3)=(x+a)(x-b)

On comparing both sides we get

a=6,b=3

The numbers that should be placed in the boxes, from left to right 6 and 3. Therefore the correct option is 3.

dexar [7]3 years ago
6 0
Your answer is 783 hope this helps 
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Step-by-step explanation:

m1=m2=m3=m5

m4=m6=m7

find m1,m2,m3 or m5

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5 0
3 years ago
Find the lateral area of a rectangular prism with l=6, w=4, h=2
lord [1]

Answer:

40 square units

Step-by-step explanation:

The surface area is given by

LA = 2(wh+lh)

where h is the height l is the length and w is the width

We do not include the top or bottom

We know l=6 w=4 and h=2

LA = 2 ( 4*2 + 6*2)

lA = 2( 8+12)

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4 0
3 years ago
Subtract. Write your answer in simplest form.<br><br> 6 3/4 - 2 3/20<br><br> I need a mixed number
umka21 [38]

Answer:

4 3/5

Step-by-step explanation:

6 3/4-2 3/20=x

3/4=15/20

15/20-3/20=12/20=6/10=3/5

6-3=3+3/5=4 3/5

6 0
3 years ago
Read 2 more answers
Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le
Svet_ta [14]

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes  =68

Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}

68= \frac{\text{Sum of all lengths}}{7}

68 \times 7 =\text{a+b+c+d+e+f+g}

476=\text{a+b+c+d+e+f+g} --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

476=x+x+x+84+84+84+4x+14

476=7x+266

\frac{476-266}{7}=x

30=x

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

7 0
3 years ago
Need help with True or False on roots!
emmasim [6.3K]
1) True
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4 years ago
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