1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kykrilka [37]
3 years ago
12

.........................help

Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0
Hey buddy
Your answer is last part(e part)
Irrational
Hope it helps :)
You might be interested in
A city planner designs a park that is a quadrilateral with vertices at j(-3,1), k(1,3), l(5,-1), m(-1,-3). There is an entrance
Maksim231197 [3]
By definition, a quadrilateral is a two-dimensional figure that is composed of four sides. Since you are given with the coordinates of the vertices, the first logical thing to do is to plot the points in a Cartesian plane as shown in the attached picture. Next, find the midpoints of each side of the quadrilateral as denoted by the red dots. Then, create a line connecting the opposite midpoints which represents the length of the paths. 

Our first solution is to find the midpoint of each sides. This is done by taking the average of each coordinate. The equation would be:

x,midpoint = (x₁+x₂)/2
y,midpoint = (y₁+y₂)/2

So, applying the equation:

midpoint jk = (-3+1/2, 1+3/2) = (-1,2)
midpoint kl = (1+5/2, 3+⁻1/2) = (3,1)
midpoint ml = (5+⁻1/2, ⁻1+⁻3/2) = (2,-2)
midpoint jm = (⁻3+⁻1/2, 1+⁻3/2) = (-2,-1)

Next, we find the lengths of the paths by using the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Distance between jk and ml = √(⁻1-2)² + (2 - ⁻2)² = 5
Distance between jm and kl = √(3-⁻2)² + (1-⁻1)² = √29
Total distance = 5 + √29 = 10.385 units

Since the scale is 1 unit = 10 meters, the actual total length of paths is equal to:

Actual Total Distance = 10.385*10
Actual Total Distance = 103.85 meters


4 0
3 years ago
Solve 3 over x minus 3 equals the quantity of x over x minus 3, minus three-halves. for x and determine if the solution is extra
astraxan [27]
\frac{3}{x} -3 = \frac{x}{x}  -  \frac{3}{2}
3 -3x = x - \frac{3x}{2}
-6x -2x -x = 6
-9x=6
9x=6
x= \frac{6}{9}= \frac{2}{3}
3 0
3 years ago
Water flows from the faucet at the rate of 5 L every 25 seconds at this rate how much water will flow from the faucet in 45 seco
Citrus2011 [14]
5L:25Seconds=1L:5seconds
In 50 seconds there will be 10L of water
In 45 We will have to subtract 1L because we are exceeding 5 seconds and in 5 seconds 1L of water comes out
10L-1L=9L
There will be 9L of water
6 0
3 years ago
3-2y-1+5x^2-7y+7+4x^2
MakcuM [25]

Answer: Hi!

The only thing we can do to simplify the equation is combine like terms.

5x^2 + 4x^2 = 9x^2

-2y - 7y = -9y

3 - 1 + 7 = 9

Our equation now looks like this:

9x^2 - 9y + 9

We have nothing left to simplify, so we're done!

Hope this helps!

8 0
3 years ago
in the year 2006 there were 163,476 wildfires in a county. This was 12520 less than four times the number of wildfires in the ye
sesenic [268]

x= wildfires in 2003

163,476= 4x - 12,520

(163,476 + 12,520) / 4

x = 43,999 your answer is 43,999

4 0
3 years ago
Other questions:
  • Factor<br> 6x2 – 17x – 14
    13·2 answers
  • In the following data set, what is the range? 3, 7, 8, 4, 4, 5, 9, 10, 6, 2
    8·1 answer
  • If parallel lines a and b are cut by transversal t, then which statement about angles 1 and 2 must be true?
    5·1 answer
  • If anyone could help I’d appreciate it! Thanks
    14·1 answer
  • Solve for x. Write both solutions, separated by a comma. 8x^2+7x-1=0
    14·1 answer
  • After the first week of registration, 92 children had enrolled for the second
    10·1 answer
  • Find the greatest number by which 90, 120 and 150 are exactly divisible.​
    10·2 answers
  • The perimeter of the rectangle is 28 units.
    5·1 answer
  • If 5 is added twice a number , the result is 29. Find the number​
    10·1 answer
  • Let s represent the price of a meal in the local
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!