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3 years ago

What are the fundamental particles of an atom

Chemistry

1 answer:

tatyana61 [14]3 years ago

5 0

Protons, neutrons, and electrons are the fundamental subatomic particles.

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An atom of the element iron has an atomic number of 26 and an atomic weight of 56. if it is neutral, how many protons, neutrons,

guapka [62]

Proton 26
neutron 0
you can tell how many proton by the atomic number

3 0

3 years ago

Mercury thermometers work because mercury ____ when it is warmed

kap26 [50]

Mercury expands when it is heated. This process is called thermal expansion.

5 0

3 years ago

Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2

lapo4ka [179]

Answer: Concentration of $CO$ = 0.328 M

Concentration of $Cl_2$ = 0.328 M

Concentration of $COCl_2$ = 0.532 M

Explanation:

Moles of $CO$ and $Cl_2$ = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of $CO$ and $Cl_2$ = $\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M$

The given balanced equilibrium reaction is,

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.860M 0.860M 0

At eqm. conc. (0.860-x) M (0.860-x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get :

$4.95=\frac{x}{(0.860-x)^2}$

By solving the term 'x', we get :

x = 0.532 M

Thus, the concentrations of $CO,Cl_2\text{ and }COCl_2$ at equilibrium are :

Concentration of $CO$ = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of $Cl_2$ = (0.860-x) M = (0.860-0.532) M = 0.328 M

Concentration of $COCl_2$ = x M = 0.532 M

3 0

3 years ago

Use the periodic table in the tools bar to answer these questions. How many moles of AgNO3 are present in 1.50 L of a 0.050 M so

IgorC [24]

M= moles de soluto / litros de solucion
moles de soluto = M. litros de solucion

Moles de soluto = 0.050 M x 1.50 L = 0.075 moles de AgNo3

4 0

3 years ago

Read 2 more answers

You know that 8.9 moles of solute particles are dissolved in that liquid solution. If the molarity of the solution is 25 M, how

pychu [463]

Answer:

V = 0.356 L

Explanation:

In this case, we need to use the following expression:

M = n/V (1)

Where:

M: molarity of solution (mol/L or M)

n: moles of solute (moles)

V: Volume of solution (Liters)

From these expression, we can solve for V:

V = n/M (2)

Now, replacing the given data we can solve V:

V = 8.9 / 25

V = 0.356 L

5 0

3 years ago

What are the fundamental particles of an atom​

What are the fundamental particles of an atom