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leonid [27]
3 years ago
7

mplete the work to solve for y: 2 5 ( 1 2 y + 5 ) − 4 5 = 1 2 y − 1 + 1 10 y 1.Distributive property: 1 5 y + 2 − 4 5 = 1 2 y −

1 + 1 10 y 2.Combine like terms: 1 5 y + 6 5 = 3 5 y − 1 3.Subtraction property of equality: 6 5 = 2 5 y − 1 Addition property of equality: 11 5 = 2 5 y 4.Division property of equality: What is the value for y?
Mathematics
2 answers:
Wewaii [24]3 years ago
7 0

Answer: 104 I think

Step-by-step explanation:

Nastasia [14]3 years ago
5 0

Answer:

11/2

Step-by-step explanation:

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When constructing a graph that compares the land areas of the five largest countries, you choose to depict the five areas with s
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5 0
3 years ago
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A helicopter is flying above a town. the local high school is directly to the east of the helicopter at a 20° angle of depressio
guapka [62]
Answer: 4.5 miles

Explanation:

When you draw the situation you find two triangles.

1) Triangle to the east of the helicopter

a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°

b) hypotensue = distance between the high school and the helicopter

c) opposite-leg to angle 20° = heigth of the helicopter

d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x

2) triangle to the west of the helicopter

a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°

b)  distance between the helicopter and the elementary school = hypotenuse

c) opposite-leg to angle 62° = height of the helicopter

d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x

3) tangent ratios

a) triangle with the helicpoter and the high school

tan 20° = Height / x ⇒ height = x tan 20°

b) triangle with the helicopter and the elementary school

tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°

c) equal the height from both triangles:

x tan 20° = (5 - x) tan 62°

x tan 20° = 5 tan 62° - x tan 62°

x tan 20° + x tan 62° = 5 tan 62°

x  (tan 20° + tan 62°) = 5 tan 62°

⇒ x = 5 tant 62° / ( tan 20° + tan 62°)

⇒ x = 4,19 miles

=> height = x tan 20° = 4,19 tan 20° = 1,525 miles

4) Calculate the hypotenuse of this triangle:

hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²

hipotenuse = 4.46 miles

Rounded to the nearest tenth = 4.5 miles

That is the distance between the helicopter and the high school.
5 0
3 years ago
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