Answer:
Step-by-step explanation:
There is an error in the question. The table does not show two linear functions. y₁ is a linear function, but y₂ is not a straight line. It makes a bend at (-6,1).
Line 1 goes through (-12,-3) and (0,5).
slope = (5-(-3))/(0-(-12)) = 2/3
y-intercept = 5
y₁ = (2/3)x + 5
Line 2 goes through (-12,-2) and (-6,1).
slope = (1-(-2))/(-6-(-12)) = 1/2
y₂ = (1/2)x + 4
(2/3)x + 5 = (1/2)x + 4
x = -6
y = (2/3)x + 5 = 1
Solution: (-6,1)
Answer:
As Given, x+y=w+z
To Prove: AOB is a line or x+y=180
∘
(linear pair.)
According to the question,
x+y+w+z=360
∘
∣ Angles around a point.
(x+y)+(w+z)=360
∘
(x+y)+(x+y)=360
∘
∣ Given x+y=w+z
2(x+y)=360
∘
(x+y)=180
∘
Hence, x+y makes a linear pair.
Therefore, AOB is a straight line
Here we might have to find p(v intersection w) and for that we use the following formula
p(v U w) = p(v)+p(w)-p(v intersection w)
And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .
Substituting these values in the formula, we will get
0.14 = 0.13 +0.04 -p(v intersection w)
p(v intersection w) =0.13 +0.04 -0.14 = 0.03
So the required answer of the given question is 0.03 .
The answer is b
Explanation: