Answer:
The volume of the larger solid is 
Step-by-step explanation:
<u><em>The question is</em></u>
If these solids are similar, find the volume of the larger solid
step 1
Find the scale factor
we know that
If two solids are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor
Let
x ----> the height of the larger solid in mm
y ----> the height of the smaller solid in mm
z ---> the scale factor

we have

substitute
---> scale factor
step 2
Find the volume of the larger solid
we know that
If two solids are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
x ----> the volume of the larger solid in cubic millimeters
y ----> the volume of the smaller solid in in cubic millimeters
z ---> the scale factor

we have

substitute the values

solve for x



Answer:
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Step-by-step explanation:
Given:
Volume of inside of the sphere is given as

where r is the radius of the sphere
To Find:
r =?
Solution:
We have
......Given
![3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}](https://tex.z-dn.net/?f=3%5Ctimes%20V%3D4%5Cpi%20r%5E%7B3%7D%20%5C%5C%5C%5C%5Ctherefore%20r%5E%7B3%7D%3D%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%20%5C%5C%5C%5C%5Ctherefore%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D%20%5Ctextrm%7Bwhich%20is%20the%20expression%20for%20r%7D)
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
.67%
hope this helps.
0.6/0.9= 0.666667
Answer:
C 40
Step-by-step explanation:
1 blue : 2 white
multiply both sides of the proportion by 20 to reach 20 blue marbles
20 blue: 40 white
Answer:
-1/2
Step-by-step explanation:
the slope of the line 2x-y=5 is 2
a perpendicular line has the negative reciprocal of the slope of the other line
hopefully this helps :)