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3 years ago

The unit used to measure barometric or air pressure

Chemistry

1 answer:

Bumek [7]3 years ago

7 0

Answer:

A barometer is an instrument used to measure air pressure and track weather systems. The most common unit of measurement used in barometers is the millibar (mb).

Explanation:

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Which of the following elements possesses an expanded octet?

stepan [7]

I think xe possess expanded octet

8 0

3 years ago

10g of a non-volatile and non-dissociating solute is dissolved in 200g of benzene.

ehidna [41]

<u>Answer: </u>The molar mass of solute is 115 g/mol.

<u>Explanation:</u>

Elevation in the boiling point is defined as the difference between the boiling point of the solution and the boiling point of the pure solvent.

The expression for the calculation of elevation in boiling point is:

$\text{Boiling point of solution}-\text{boiling point of pure solvent}=i\times K_b\times m$

$\text{Boiling point of solution}-\text{Boiling point of pure solvent}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Boiling point of pure solvent (benzene) = $80.10^oC$

Boiling point of solution = $81.20^oC$

i = Vant Hoff factor = 1 (for non-electrolytes)

$K_b$ = Boiling point elevation constant = $2.53^oC/m$

$m_{solute}$ = Given mass of solute = 10 g

$M_{solute}$ = Molar mass of solute = ? g/mol

$w_{solvent}$ = Mass of solvent = 200 g

Putting values in equation 1, we get:

$81.20-80.10=1\times 2.53\times \frac{10\times 1000}{M_{solute}\times 200}\\\\M_{solute}=\frac{1\times 2.53\times 10\times 1000}{1.1\times 200}\\\\M_{solute}=115g/mol$

Hence, the molar mass of solute is 115 g/mol.

4 0

3 years ago

Use the periodic table to identify the number of core electrons and the number of valence electrons in each case below.

Harman [31]

Can you please add a picture of the case??

5 0

2 years ago

If one gram of sulphur dioxide contains x molecules what will be the number of molecules in 1g of methane

evablogger [386]

The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :

(i) The molecular formula of sulphur dioxide is $SO_{2}$

So, $1$ mole of $SO_{2}$ = $Mass$ $of$ $2'O'$

$=32+2*16$

$= 64$ grams

Now, $64g$ of sulphur dioxide $= 1$ mole

So, $1g$ of sulphur dioxide = $\frac{1}{64}$ mole

Thus, we have $\frac{1}{64}$ mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, $\frac{1}{64}$ mole of methane will also contain x molecules of methane.

(ii) Molecular formula of methan is $CH_{4}$

So, 1 mole of $CH_{4}$ = Mass of C + Mass of 4 H

$=12+4*12$

Now, 16g of methane = 1 mole

So, 1 g of mathane = $\frac{1}{16}$ mole

We know that:

$\frac{1}{64}$ mole of methane contains = x molecules

So, $\frac{1}{16}$ mole of contains will contain = $\frac{x*64}{16}$ molecules

= $4x$ molecules

7 0

2 years ago

Calculate the molarity of a solution made by adding 45.4 g of nano3 to a flask and dissolving it with water to create a total vo

aleksandr82 [10.1K]

Solutions are made up of two non reacting species called solute and solvent. The amount of solute in solvent is known as concentration of that solute. Concentration is often measured in Molarity. Molarity is the amount of solute dissolved in 1 dm3 of solution. Answer to your question is as follow;

3 0

3 years ago

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