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evablogger [386]
3 years ago
13

The reaction A → products is first order. If the initial concentration of A is 0.646 M and, after 72.8 seconds have elapsed, the

concentration of A has fallen to 0.0146 M, what is the rate constant of the reaction?
Chemistry
1 answer:
mario62 [17]3 years ago
5 0

Answer: 0.00867 moldm-3

Explanation:

Since the reaction is 1st order,

Rate of reaction=∆[A]÷t

0.646-0.0146/72.8= 0.00867

Remember that in a first order reaction, the rate of reaction depends on change in the concentration of only one of the reaction species, A in the problem above.

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When 0.50 L of a 12 M solution is diluted to 1.0 L, what is the resulting molarity?
Lyrx [107]

Answer:

The resulting molarity is 6M.

Explanation:

A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).

We use the formula for dilutions:

C1 x V1 = C2 x V2

12 M x 0,5L = C2 x 1,0 L

C2= (12 M x 0,5 L)/1,0 L

<em>C2= 6 M</em>

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3 years ago
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hope this helps
4 0
3 years ago
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PLEASE ANSWER ASAP!!!!!!! 50 points if the answer is correct!
Ad libitum [116K]

5

 mL acetic acid

95

mL water

Explanation:

Since

5

%

of the vinegar, by volume, is acetic acid, and we have

100

mL of vinegar, we have

5

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Similarly, we have

100

%

−

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=

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%

being water, so we have

95

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3 years ago
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tekilochka [14]

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Explanation:

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6 0
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Anestetic [448]

Answer:

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