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evablogger [386]
3 years ago
13

The reaction A → products is first order. If the initial concentration of A is 0.646 M and, after 72.8 seconds have elapsed, the

concentration of A has fallen to 0.0146 M, what is the rate constant of the reaction?
Chemistry
1 answer:
mario62 [17]3 years ago
5 0

Answer: 0.00867 moldm-3

Explanation:

Since the reaction is 1st order,

Rate of reaction=∆[A]÷t

0.646-0.0146/72.8= 0.00867

Remember that in a first order reaction, the rate of reaction depends on change in the concentration of only one of the reaction species, A in the problem above.

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Answer:

This reaction is exothermic because the system shifted to the left on heating.

Explanation:

2NO₂ (g) ⇌ N₂O₄(g)

Reactant => NO₂ (dark brown in color)

Product => N₂O₄ (colorless)

From the question given above, we were told that when the reaction at equilibrium was moved from room temperature to a higher temperature, the mixture turned dark brown in color.

This simply means that the reaction does not like heat. Hence the reaction is exothermic reaction.

Also, we can see that when the temperature was increased, the reaction turned dark brown in color indicating that the increase in the temperature favors the backward reaction (i.e the equilibrium shift to the left) as NO₂ which is the reactant is dark brown in color. This again indicates that the reaction is exothermic because an increase in the temperature of an exothermic reaction will shift the equilibrium position to the left.

Therefore, we can conclude that:

The reaction is exothermic because the system shifted to the left on heating.

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