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IgorLugansk [536]
3 years ago
8

Combustion reaction of ammonia

Chemistry
1 answer:
geniusboy [140]3 years ago
4 0
It produces nitrogen gas and water
4NH3+3O2+heat 2N2+6H 2O
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Help me with this question please
mash [69]

<u>Answer:</u>

a. Oxidising agent: Cl₂

b. Reducing agent: NaBr

c. Oxidised: NaBr

d. Reduced: Cl₂

e. Oxidation numbers before reaction: Cl= 0, Na= +1, Br= -1

f. Oxidation numbers after reaction: Cl= -1, Na= +1, Br= 0

<u>Explanation:</u>

Oxidising agents reduces themselves, oxidising other elements/compounds.

Reducing agents oxidise themselves, reducing other elements/compounds.

Oxidation is the <u>loss</u> of electrons or an <u>increase</u> in oxidation number.

Reduction is the <u>gain</u> of electrons or <u>decrease</u> in oxidation number.

6 0
1 year ago
What investigations never involve hypotheses?
marshall27 [118]
The correct answer is a descriptive investigation.

An investigation which does not involve hypotheses called descriptive investigation.
Hypotheses are termed as scientific hypotheses and require that one can test it. In hypothesis, previous observation can not satisfactorily be explained with an available scientific theory.
Working hypotheses are being proposed for further research.
5 0
3 years ago
Read 2 more answers
Calculate the amount in moles of 125 g of CaSO4.
Leto [7]

Answer:

Number of moles = 0.92 mol

Explanation:

Given data:

Mass of CaSO₄ = 125 g

Number of moles of CaSO₄ = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of CaSO₄:

Molar mass of CaSO₄ = 40 + 32+ 16×4

Molar mass of CaSO₄ = 40 + 32+ 64

Molar mass of CaSO₄ = 136 g/mol

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 125 g/ 136 g/mol

Number of moles = 0.92 mol

7 0
3 years ago
FORENSIC SCIENCE HELP
Annette [7]
That is correct c
Explanation
7 0
2 years ago
How many atoms of hydrogen are present in 7.63 g of ammonia? please help me ??
GarryVolchara [31]
The atoms  of  hydrogen  that are  present  in  7.63 g  of ammonia(NH3)

find  the  moles  of NH3 =mass/molar mass
 7.63 g/ 17 g/mol = 0.449  moles

since there  is  3 atoms of H  in NH3 the  moles of  H = 0.449 x 3 = 1.347 moles

by  use  of  1 mole = 6.02 x10^23  atoms
what  about  1.347  moles

= 1.347  moles/1   moles  x 6.02 x10^23 atoms = 8.11 x10^23  atoms of Hydrogen
3 0
3 years ago
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