Answer:
Convection and Radiation mechanisms carry most of the heat
Explanation:
This is because Convection proceeds strongy as heated air rises from the hot element while Radiation is also strong, although the material of the cooking pots will how effective it is.
Answer:
Explanation:
Not really sure what you're trying to do. You propagate uncertainties for indirect measurements, as in when you calculate a value from other values.
What you have here is a series of values of direct measurements it seems.
Anyway, for error bars will have a width of 2 times the uncertainty reported.
For example on the first one
373.67 +/- 15.444
You would have an error bar with a width of 2 * 15.444 = 30.888. This bar would be centered at 373.677. The lowest point of the error bar would be at 358.233 and the highest point at 389.121.
You also mentioned a scatter plot, but scatter plots are 2D at least. Are these measurements associated to something else like time? You need 2 coordinates for each point in a scatter plot.
Answer:
The answer to your question is weight = 1667 N
Explanation:
Data
density = 2.40 x 10³ kg/m³
volume = 0.0708 m³
Force = 66.7 N
weight of the block = ?
- Formula
density = mass / volume
- Solve for mass
mass = density x volume
-Substitution
mass = (2.40 x 10³)(0.0708)
-Result
mass = 169.92 kg
-Calculate the weight of the body
weight = mass x gravity
-Substitution
weight = 169.92 x 9.82
-Simplification
weight = 1666.9 N ≈ 1667 N
Answer:
height is 69.68 m
Explanation:
given data
before it hits the ground = 46 % of entire distance
to find out
the height
solution
we know here acceleration and displacement that is
d = (0.5)gt² ..............1
here d is distance and g is acceleration and t is time
so when object falling it will be
h = 4.9 t² ....................2
and in 1st part of question
we have (100% - 46% ) = 54 %
so falling objects will be there
0.54 h = 4.9 (t-1)² ...................3
so
now we have 2 equation with unknown
we equate both equation
1st equation already solve for h
substitute h in the second equation and find t
0.54 × 4.9 t² = 4.9 (t-1)²
t = 0.576 s and 3.771 s
we use here 3.771 s because 0.576 s is useless displacement in the last second before it hits the ground is 46 % of the entire distance it falls
so take t = 3.771 s
then h from equation 2
h = 4.9 t²
h = 4.9 (3.771)²
h = 69.68 m
so height is 69.68 m
