Immediately omit the negative possible answer. Since 5^2 = 25, 1/5^2 = 1/25.
Answer:
21 Students
Step-by-step explanation:
140 x .15 = 21
Answer:
Option C. Stem Leaves 6 7 7 2 5 8 5 7 9 9 9 0 9 10 0
Option D.
Step-by-step explanation:
The data values are 67, 72, 85, 75, 89, 89, 87, 90, 99 and 100.
Arranging the data values in ascending order
67, 72, 75, 85, 87, 89, 89, 90, 99, 100
The stem and lead plot can be shown under and stem is denoted as "S" whereas leaves are denoted as "L".
S L
6 7
7 2 5
8 5 7 9 9
9 0 9
10 0
The longer row of stem indicates the higher frequencies and so the length of rows are similar to the heights of bars in histogram.
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
Answer:
beggining poit:3 second point (potentially): 1,5
Step-by-step explanation:
in the y intercept 3 is it so which ever has a 3 as the starting point there could be an option
for the 2x part that is the slope otherwise known as rise over run so what you do is that you turn it to a fraction over or under 1 meaning you rise for 2 and go to the right 1
rise 2
_
run 1
in order to rise 2 you go up 2 from the y intercept(3) and in order to run you go right since its a positive
once you plot those two dots then you draw a line across
